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shutvik [7]
2 years ago
9

Evaluate the following equation for the given x value. Round your answer to

Mathematics
1 answer:
exis [7]2 years ago
6 0

Answer:

585856859686

Step-by-step explanation:

546786676

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Rewrite using the distributive property and GCF 16 + 40
Artist 52 [7]

The GCF of 16 and 40 is 8.

16/8 = 2

40/8 = 5

We can rewrite this using the distribute property like so:

<h3><u>8(2 + 5)</u></h3>

Using the distributive property:

16 + 40

16 + 40 = 56

We can also add inside the parentheses and multiply and we'll get the same answer.

8(7)

56


8 0
3 years ago
Write a linear function that relates y to x <br><br> y=
son4ous [18]

y=x-2

hope this helped :)

7 0
2 years ago
Which of these supporting details BEST fits after sentence 2?
jeyben [28]

Answer:

c

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h
mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed  = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere  =\frac{2}{3}\pi r^3

Volume of a Cylinder =\pi r^2 h

Therefore:

The Volume of the Solid formed

=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}

Area of the Hemisphere =2\pi r^2

Curved Surface Area of the Cylinder =2\pi rh

Total Surface Area=

2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh

Cost of the Hemispherical Ends  = 2 X  Cost of the surface area of the sides.

Therefore total Cost, C

=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh

Recall: h=\frac{4640}{\pi r^2}-\frac{4r}{3}

Therefore:

C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}

The minimum cost occurs at the point where the derivative equals zero.

C^{'}=\frac{-27840+32\pi r^3}{3r^2}

When \:C^{'}=0

-27840+32\pi r^3=0\\27840=32\pi r^3\\r^3=27840 \div 32\pi=276.9296\\r=\sqrt[3]{276.9296} =6.518

Recall:

h=\frac{4640}{\pi r^2}-\frac{4r}{3}\\h=\frac{4640}{\pi*6.518^2}-\frac{4*6.518}{3}\\h=26.074 feet

Therefore, the dimensions that will minimize the cost are:

Radius =6.518 feet

Height = 26.074 feet

5 0
2 years ago
What is the he measure of angle C
photoshop1234 [79]

Answer:

18

Step-by-step explanation:

4 0
2 years ago
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