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zzz [600]
4 years ago
8

(13pts)pls help seems simple

Mathematics
1 answer:
Kobotan [32]4 years ago
5 0

Answer:

could you post it.i would like to help you.come on post the question

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The sum of the first 4 terms is 671? If the number increased by 20% each time, what is the starting number?
Kipish [7]

Answer:

the starting number is 751

Step-by-step explanation:

multiple 20 × 4 and get 80 then add to 671 which is 751

4 0
3 years ago
Help me using the image below
ZanzabumX [31]

Answer:

The value of x is 105°

Step-by-step explanation:

Firstly, you have to find the total angles in regular hexagon and octagon using the θ = (n-2)×180° where "n" determine numbers of edges :

hexagon,

θ = (6-2)×180°

= 4 × 180°

= 720° (total angles)

octagon,

θ = (8-2)×180°

= 6 × 180°

= 1080° (total angles)

Then, calcular the angle for each edge :

hexagon,

θ = 720° ÷ 6

= 120°

octagon,

θ = 1080 ÷ 8

= 135°

Lastly, to find the value of angle x. As the angle in a circle is 360° so you have to substract :

x = 360° - 135° - 120°

= 105°

6 0
3 years ago
What is the long division for 1. 5)65,749 2. 6)22,176 3. 5)25,931 4. 4)71,568 5. 7)98,694 6. 9)81,844
Anestetic [448]
5 65,749 13,149 R4 2. 6 22,176 3,696 R0 3. 5 25,931 5,186 R1 4. 4 71,568 17,892 R0 5. 7 98,694 14,099 R1 6. 9 81,844 9,093 R7
3 0
4 years ago
Stacie is playing a card game. There are 8 wild cards for every 40 standard cards. If there are 10 wild cards how many standard
docker41 [41]
If there are 10 wild cards there are 50 standard cards. 8 and 40 can both be divide by 4, which makes 2/10. This means that there are 2 wild cards for every 10 standard cards. If there are 50 wild cards, you simply multiply 2/10 by 5. This will give you 10/50. 10 wild cards in 50 standard cards.
8 0
3 years ago
HELP! PLEASE! Jackson is building a small rectangular basketball section in his backyard. The length of the section will be 1.25
Misha Larkins [42]

Answer:

Part A) A=1.25W^2

Part B) Length: 17.5 feet and Width: 14 feet

Step-by-step explanation:

Part A) Create an equation to represent the area of the basketball section A, in terms of the width W.

Let

L ----> the length of the  rectangular basketball section

W ---> the width of the  rectangular basketball section

we know that

The area of the rectangular basketball section is equal to

A=LW ----> equation A

The length of the section will be 1.25 times the width of the section

so

L=1.25W ----> equation B

substitute equation B in equation A

A=(1.25W)W\\A=1.25W^2

Part B) Jackson decides to make the area of the basketball section 245 square feet. What are the dimensions, in feet, of the basketball section?

we have

A=1.25W^2\\A=245\ ft^2

so

245=1.25W^2

solve for W

W^2=245/1.25\\W^2=196\\W=14\ ft

Find the value of L

substitute the value of W in the equation B

L=1.25(14)=17.5\ ft

therefore

The dimensions are :

Length: 17.5 feet

Width: 14 feet

8 0
3 years ago
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