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NemiM [27]
3 years ago
11

Piper Rose Boutique has been approached by the community college to make special polo shirts for the faculty and staff. The coll

ege is willing to buy 4,000 polos with its own design for $6.00 each. The company normally sells its shirts for $12.00 each. The company has enough excess capacity to make this order. A breakdown of the costs is as follows:
Direct materials $2.00
Direct labor 0.50
Variable factory overhead 1.50
Fixed factory overhead 2.50
Total cost per unit $6.50
Should Piper Rose Boutique accept the special order made by the college?
Business
1 answer:
Burka [1]3 years ago
3 0

Answer:

Piper Rose Boutique should accept the special order made by the college

Explanation:

Price per unit the college is willing to pay = $6

Total variable cost per unit to be incurred by Piper Rose Boutique = Direct materials + Direct labor + Variable factory overhead = $2.00 + $0.50 + $1.50 = $4,00

Since the price per unit of $6 that the college is willing to pay is greater than the total variable cost per unit of $4 to be incurred by Piper Rose Boutique, Piper Rose Boutique should accept the special order made by the college.

Note: the Fixed factory overhead is not relevant in taking the decision. Only the variable costs are relevant.

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Simon recently received a credit card with an 18% nominal interest rate. With the card, he purchased an Amazon Kindle for $350.
aniked [119]

Answer:

A.50 months

B.12.92 months

C.$112.38

Explanation:

a). Using this formula

PV of Annuity = Monthly Payment * [{1 - (1 + r)-n} / r]

Where,

PV of Annuity =$350

Monthly Payment =$10

r=(0.18/12)

Let plug in the formula

$350 = $10 * [{1 - (1 + 0.18/12)-n} / (0.18/12)]

$350 / $10 = {1 - (1.015)-n} / 0.015

35 * 0.015 = 1 - (1.015)-n

(1.015)-n = 1 - 0.525

-n[log(1.015)] = log(0.475)

-n[0.0149] = -0.7444

n = -0.7444 / -0.0149

n= 50 months

b). Using this formula

PV of Annuity = Monthly Payment * [{1 - (1 + r)-n} / r]

Where,

PV of Annuity =$350

Monthly Payment =$30

r=(0.18/12)

Let plug in the formula

$350 = $30 * [{1 - (1 + 0.18/12)-n} / (0.18/12)]

$350 / $30 = {1 - (1.015)-n} / 0.015

11.67 * 0.015 = 1 - (1.015)-n

(1.015)-n = 1 - 0.175

-n[log(1.015)] = log(0.825)

-n[0.0149] = -0.1924

n = -0.1924 / -0.0149 =

n=12.92 months

c). Calculation for the Total Amount Paid under $10-a-month plan

Using this formula

Total Amount Paid under $10-a-month plan = No. of Payments * Monthly Payment

Where,

No.of Payments =50

Monthly Payment=10

Let plug in the formula

Total Amount Paid under $10-a-month plan= 50 * $10 = $500

Calculation for the Total Amount Paid under $30-a-month plan

Using this formula

Total Amount Paid under $30-a-month plan = No. of Payments * Monthly Payment

Where,

No. of Payments =12.92

Monthly Payment=$30

Let plug in the formula

Total Amount Paid under $30-a-month plan= 12.92 * $30 = $387.62

Hence,

Total Amount Paid under $10-a-month plan -Total Amount Paid under $30-a-month plan

= $500 - $387.62

= $112.38

7 0
3 years ago
On January 1, 2019, Cullumber Company had $1,000,000 of common stock outstanding that was issued at par. It also had retained ea
Flauer [41]

Answer:

<em>a. Par value is $10, and market price is $19. b. Par value is $5, and market price is $20.</em>

Explanation:

4 0
3 years ago
Sanford Co. sells $500,000 of 10% bonds on March 1, 2020. The bonds pay interest on September 1 and March 1. The due date of the
Triss [41]

Answer:

ATTACHED file with the bonds schedule

Explanation:

First, we solve for the proceed from the issuance:

PV of the coupon:

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\

C 25,000.000 (500,000 x 10%/2)

time 7 (3 and a half year x 2 payment per year)

rate 0.06 (12% annual / 2)

25000 \times \frac{1-(1+0.06)^{-7} }{0.06} = PV\\

PV $139,559.5360

PV of maturity:

\frac{Maturity}{(1 + rate)^{time} } = PV  

Maturity   500,000.00

time   7.00

rate  0.06

\frac{500000}{(1 + 0.06)^{7} } = PV  

PV   332,528.56

PV c $139,559.5360

PV m  $332,528.5568

Total $472,088.0928

Then we construct the bonds schedule as follows:

procceds 472,088

face value 500,000

discount on bonds payable -27,912

bond rate 0.05

market rate 0.06

ionterest expense: carrying value times market rate:

472,088 x 0.06 = 28,325.29

cash outlay          25,000

amortization          3,325.29

carrying value after first payment:

472,088 + 3,325.29 = 475,413.29

and the process repeat for all periods.

3 0
3 years ago
Which investment option has the highest risk ?
Flauer [41]
Buying is the highest risk investment because the outcome is unknown and you have to take a gamble.
8 0
1 year ago
Maria is a hard-working college sophomore. One Sunday, she decides to work nonstop until she has answered 100 practice problems
sdas [7]

Answer:

The correct answers are:

i. The marginal, or additional, gain from Maria’s first hour of work, from 8:00 AM to 9:00 AM, is <u>  40  </u> problems.

ii. The marginal gain from Maria’s third hour of work, from 10:00 AM to 11:00 AM, is <u>   20   </u> problems

iii. 2 hours working on problems, 2 hours reading (c)

Explanation:

i. The marginal gain from 8:00 AM to 9:00 AM is calculated thus:

work done at 8:00 AM = 0 problems

Work done at 9:00 AM = 40 problems

Marginal gain = (Work done at 9:00 AM) - (work done at 8:00) = 40 - 0 = 40 problems

ii. work done at 10:00 AM = 70 problems

work done at 11:00 AM = 90 problems

Marginal gain = 90 - 70 = 20 problems

iii. To get the best exam score, the most number of problems possible in total must be answered within the 4-hour period, and this is determined as follows:

we are told that Maria gets tired as time progresses and the number of questions answered reduces we notice the following numbers of questions answered in each hour:

8:00 AM to 9:00 AM = 40 - 0 = 40 problems (hour 1)

9:00 AM to 10:00 AM = 70 - 40 = 30 problems (hour 2)

10:00 AM to 11:00 AM = 90 - 70 = 20 problems (hour 3)

11:00 AM to Noon = 100 - 90 = 10 problems (hour 4)

Also, we are told that;

1 hour of reading = 25 problems

Comparing the reading and solving problems, we see that the number of problems solved in hour-1 and hour-2  (40 and 30 respectively) are more than the equivalent number of problems solved in reading for 1 hour, while hour-3 and hour-4 (20 and 10 respectively), have lesser equivalent number of problems each, than reading for one hour. Therefore to make the most out of the 4 hours, Maria will spend the first 2 hours solving problems and the next two hours reading, giving a total of: 40 + 30 + 25 + 25 = 120 problems solved.

4 0
3 years ago
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