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Colt1911 [192]
3 years ago
7

Find the product (b+2)(-b^2+4b-3b)

Mathematics
1 answer:
maria [59]3 years ago
3 0

Step-by-step explanation:

<em>=>(b*-b²)+(b*4b)-(b*3b)-(2*-b²)+(2*4b)-(2*3b)</em>

<em>=</em><em>></em><em>-b³</em><em>+</em><em>4</em><em>b</em><em>²</em><em>-</em><em>3</em><em>b</em><em>²</em><em>-</em><em>2</em><em>b</em><em>²</em><em>+</em><em>8</em><em>b</em><em>-</em><em>6</em><em>b</em>

<em>=</em><em>></em><em>-b</em><em>³</em><em>+</em><em>b²</em><em>-</em><em>2</em><em>b</em><em>²</em><em>+</em><em>2</em><em>b</em>

<em>=</em><em>></em><em>-b³</em><em>-</em><em>b²</em><em>+</em><em>2</em><em>b</em>

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Every day going to school, June has to go by boat (point A) over a 217m-wide river to point B (the other bank), and then from B
Anit [1.1K]

Answer:

  • 647m

Explanation:

The distance traveled by June, from A to D, is the sum of the distance from A to C plus the distance from C to D:

  • Travel from A to D = Distance AC + Distance DC.

<u>1) Find the distance AC</u>

  • Triangle ABC is a right triangle, from which you have to calculate the hypotenuse (AC), knowing angle A (50º), and its adjacent leg (217 m).
  • cos (50º) = 217m / AC
  • AC = 217m / cos (50º) = 337.59m

<u>2) Find the distance DC</u>

First, you need to calculate the side BC which is a common side of both triangles ABC and DBC.

You can use Pythagora's or a trigonometric function (tangent or sine).

  • tan (50º) = BC / 217 m ⇒ BC = 217 m × tan (50º) = 258.61 m

Now you can use Pythagora's theorem to find the distance DC, which is the hypotenuse of the triangle DBC:

  • DC² = (170m)² + (258.62)² = 95,779.41m²
  • DC = 309.48m

<u>3) Find the total distance traveled from A to D</u>

  • Travel from A to D = Distance AC + Distance DC = 337.59m + 309.48m = 647.07 m ≈ 647m.
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Answer:

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Step-by-step explanation:

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