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mash [69]
2 years ago
6

I have no clue Question 7

Mathematics
1 answer:
Fed [463]2 years ago
5 0

Answer: 27a^{-6}b^{3}

Step-by-step explanation:

you can isolate the separate terms so you get

3^3 x a^(-2x3) x b^3 = 27 a^-6b^3

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Combine like terms to simplify the expression:
Ahat [919]
Im pretty sure its -y^2+3y+13x-3
8 0
3 years ago
a square field has a side 150 m long .There is a road 5 m wide all around the park outside it .Find the cost of constructing the
alisha [4.7K]

Answer:

Cost to construct the road = 775000 rupees

Step-by-step explanation:

Square field has a side = 150 m

Area of the field = (Side)²

                           = (150)²

                           = 22500 m²

Length of the park with road around the field = 150 + 2×(width of the road)

                                                                            = 150 + (2×5)

                                                                            = 160 m

Similarly, width of the park with road around the field = 160 m

Area of the park with road = (Side)²

                                            = (160)²

                                            = 25600 m²

Area of road = Area of the park with road - Area of the park

                     = 25600 - 22500

                     = 3100 m²

Since, cost of constructing the road = 250 rupees per square meter

Cost to construct the road with the given area = 250 × 3100

                                                                              = 775000 rupees

6 0
2 years ago
Please Help!!!!!!!!!!!!!!!!
trapecia [35]

Answer: ( D) 998 is the greatest three digit positive integer

Step-by-step explanation: Your welcome.

7 0
2 years ago
What is the value of the arithmetic series below?
RoseWind [281]

Answer:

- 494

Step-by-step explanation:

Breaking down the summation into it;s component parts

= 4k - \frac{3}{2} k(k + 1) ← substitute k = 19

= (4 × 19 ) - 1.5 × (19 × 20)

= 76 - (1.5 × 380)

= 76 - 570

= 494

3 0
3 years ago
Read 2 more answers
How many different arrangements are there of the letters a, b, c, d, e, f for which e is not last in line?
Olegator [25]
Hmm, there are 5 letters


if you cannot repeat the letters
hmm, let's find how many for 4 letters
there are 4! or 4*3*2*1=24
that's how many ways there are to arrange a,b,c, d
now we can multiply it by 4 because there are 4 choices for the last place (e is not included0
24*4=56
answer is 56 different arrangements
6 0
3 years ago
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