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mash [69]
2 years ago
6

I have no clue Question 7

Mathematics
1 answer:
Fed [463]2 years ago
5 0

Answer: 27a^{-6}b^{3}

Step-by-step explanation:

you can isolate the separate terms so you get

3^3 x a^(-2x3) x b^3 = 27 a^-6b^3

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I NEED HELP ASAP! THANKS :)
4vir4ik [10]

Answer:

Last option: increasing: -2 < x < 0 and x> 3/2;

decreasing: x < -2 and 0 < x < 3/2

Step-by-step explanation:

The function given is an absolute cubic function. (Pictured below).

We can determine from the graph that the equation increases over the interval:

increasing: -2 < x < 0 and x> 3/2;

decreasing: x < -2 and 0 < x < 3/2

6 0
2 years ago
Read 2 more answers
A number is as much greater than 21 as it is less than 75 .find the number​
laiz [17]

Answer:

46

Step-by-step explanation:

Let number is x greater than 21 and x less than 71.

Now, according to question,

21+x=71−x

2x=50

x=25

So, required number is 21+x=21+25=46.

Alternatively,

The required number would be the average or mean of 21 and 71.

So, required number =

2

(21+71)

=46.

7 0
3 years ago
How do I simplify the n^-6*n^3 topic "Negative and Zero Exponents"
Alchen [17]
Since you’re multiplying n^-6 and n^3, you can add the exponents: -6+3 = -3

n^-6 * n^3 = n^-3

If you need to finish without having a negative exponent in your answer, then remember a negative exponent means that factor is on the wrong side of the fraction.

n^-3 = n^-3 / 1 = 1/n^3

when the factor moves to the other side of the fraction, the side of the exponent changes.
7 0
2 years ago
Consider two bases B = {b1, b2, b3} and C = {c1, c2, c3} for a vector space V such that
Helen [10]
I’m a failure if you can just say “yes you are” in the comments
3 0
2 years ago
If f(x) = 3x-1 and g(x)= x+2 find (f-g)(x)​
wariber [46]

Answer:

2x-3

Step-by-step explanation:

f(x) = 3x-1

g(x) = x+2

Find (f-g)(x), this means we need to subtract g from x.

(3x-1) - (x+2)

Subtract the like terms:

3x -x = 2x

-1 -2 = -3

Combine them to get 2x-3

7 0
3 years ago
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