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zloy xaker [14]
4 years ago
12

A recipe for snack mix call for 4 3/4 cups of cereal the amount of peanuts needed is 1 and 2/3 cups less than the amount of cere

al needed
How many cups of peanuts are needed?

How many cups of cereal and peanuts are needed
Mathematics
2 answers:
BaLLatris [955]4 years ago
8 0

Answer: 1st question=3 1/12 2nd question=6.4166667

Step-by-step explanation: Please correct me if I’m wrong, if I’m right, thank me.

morpeh [17]4 years ago
3 0

Answer:

3¹/₁₂ cups; 7⅚ cups

Step-by-step explanation:

1. Cups of peanuts

4¾

<u>-1⅔ </u>

(a) Convert the fractions to their lowest common denominator

The lowest common denominator is 12.

 4⁹/₁₂

<u>-1⁸/₁₂ </u>

(b) Subtract the numbers

4⁹/₁₂

<u>-1⁸/₁₂ </u>

3¹/₁₂

You need 3¹/₁₂ cups of peanuts.

2. Cups of cereal and peanuts

 4¾

<u>+3¹/₁₂ </u>

(a) Convert the fractions to their lowest common denominator

The lowest common denominator is 12.

 4⁹/₁₂

<u>+3 ¹/₁₂ </u>

(b) Add the numbers

 4⁹/₁₂

<u>+3 ¹/₁₂ </u>

 7¹⁰/₁₂

(c) Reduce the fraction to lowest terms

Divide the numerator and denominator by 2.

7¹⁰/₁₂ = 7⅚

The total volume of cereal and peanuts is 7⅚ cups.

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Using the addition rule of the Sine function and the Cosine function, we obtain \cos\dfrac{x+y}{2}=\dfrac{b}{\sqrt{a^2+b^2}}.

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Dividing the equation (1) by (2), we get:

\dfrac{\sin\dfrac{x+y}{2}}{\cos\frac{x-y}{2}}=\dfrac{a}{b}\\\Longrightarrow \tan\dfrac{x+y}{2}=\dfrac{a}{b}             (3)

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