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zloy xaker [14]
3 years ago
12

A recipe for snack mix call for 4 3/4 cups of cereal the amount of peanuts needed is 1 and 2/3 cups less than the amount of cere

al needed
How many cups of peanuts are needed?

How many cups of cereal and peanuts are needed
Mathematics
2 answers:
BaLLatris [955]3 years ago
8 0

Answer: 1st question=3 1/12 2nd question=6.4166667

Step-by-step explanation: Please correct me if I’m wrong, if I’m right, thank me.

morpeh [17]3 years ago
3 0

Answer:

3¹/₁₂ cups; 7⅚ cups

Step-by-step explanation:

1. Cups of peanuts

4¾

<u>-1⅔ </u>

(a) Convert the fractions to their lowest common denominator

The lowest common denominator is 12.

 4⁹/₁₂

<u>-1⁸/₁₂ </u>

(b) Subtract the numbers

4⁹/₁₂

<u>-1⁸/₁₂ </u>

3¹/₁₂

You need 3¹/₁₂ cups of peanuts.

2. Cups of cereal and peanuts

 4¾

<u>+3¹/₁₂ </u>

(a) Convert the fractions to their lowest common denominator

The lowest common denominator is 12.

 4⁹/₁₂

<u>+3 ¹/₁₂ </u>

(b) Add the numbers

 4⁹/₁₂

<u>+3 ¹/₁₂ </u>

 7¹⁰/₁₂

(c) Reduce the fraction to lowest terms

Divide the numerator and denominator by 2.

7¹⁰/₁₂ = 7⅚

The total volume of cereal and peanuts is 7⅚ cups.

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Answer:

Find the X and Y Intercepts 3x-5y=-20

Find the X and Y Intercepts 3x-5y=-20. 3x−5y=−20 3 x - 5 y = - 20. Find the x-intercepts. Tap for more steps

Step-by-step explanation:

5 0
3 years ago
Here's the question. ​
OleMash [197]

Answer:

The value of T₂₀ - T₁₅ is <u>-20</u>.

Step-by-step explanation:

<u>Given</u> :

  • >> If for an A.P, d = -4

<u>To</u><u> </u><u>Find</u> :

  • >> T₂₀ - T₁₅

<u>Using Formula</u> :

General term of an A.P.

\star{\small{\underline{\boxed{\sf{\red{ T_n = a  + (n - 1)d}}}}}}

  • >> Tₙ = nᵗʰ term
  • >> a = first term
  • >> n = no. of terms
  • >> d = common difference

<u>Solution</u> :

Firstly finding the A.P of T₂₀ by substituting the values in the formula :

{\dashrightarrow{\pmb{\sf{ T_n = a  + (n - 1)d}}}}

{\dashrightarrow{\sf{ T_{20} = a  + (20 - 1) d}}}

{\dashrightarrow{\sf{ T_{20} = a  + (19)d}}}

{\dashrightarrow{\sf{ T_{20} = a  + 19  \times d}}}

{\dashrightarrow{\sf{ T_{20} = a  + 19d}}}

{\star \: {\underline{\boxed{\sf{\pink{ T_{20} = a  + 19d}}}}}}

Hence, the value of T₂₀ is a + 19d.

\rule{190}1

Secondly, finding the A.P of T₁₅ by substituting the values in the formula :

{\dashrightarrow{\pmb{\sf{ T_n = a  + (n - 1)d}}}}

{\dashrightarrow{\sf{ T_{15}= a  + (15 - 1) d}}}

{\dashrightarrow{\sf{ T_{15}= a  + (14) d}}}

{\dashrightarrow{\sf{ T_{15}= a  + 14 \times d}}}

{\dashrightarrow{\sf{ T_{15}= a  + 14d}}}

{\star{\underline{\boxed{\sf \pink{ T_{15}= a  + 14d}}}}}

Hence, the value of T₁₅ is a + 14d

\rule{190}1

Now, finding the difference between T₂₀ - T₁₅ :

{\dashrightarrow{\pmb{\sf{T_{20} -  T_{15}}}}}

{\dashrightarrow{\sf{(a + 19d) -  (a + 14d)}}}

{\dashrightarrow{\sf{a + 19d -  a  -  14d}}}

{\dashrightarrow{\sf{a - a + 19d -  14d}}}

{\dashrightarrow{\sf{0+ 19d -  14d}}}

{\dashrightarrow{\sf{19d -  14d}}}

{\dashrightarrow{\sf{5 \times  - 4}}}

{\dashrightarrow{\sf{ - 20}}}

{\star \: \underline{\boxed{\sf{\pink{T_{20} -  T_{15} =  - 20}}}}}

Hence, the value of T₂₀ - T₁₅ is -20.

\underline{\rule{220pt}{3.5pt}}

3 0
2 years ago
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gladu [14]
B) is the correct answer.
6 0
3 years ago
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Step-by-step explanation:

i hope this helps :))

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Answer:

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Step-by-step explanation:

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