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2 years ago

I NEED HELP FAST

Mathematics

1 answer:

Over [174]2 years ago

7 0

Y= 13 over 10x + 2 is the answer. The most important thing to remember when finding the slope of the line is RISE over RUN. When you rise, you go up or down. When you run, you go right or left. Think of RISE over RUN as a fraction.

You find two points on the line and you count up/down a certain amount of spaces, and right/left a certain amount of spaces to go from one point to the other point.

In this equation, we could use the point on the y-axis and the last point we see on the graph located at (10,15). You count up/down vertically first until you reach the horizontal line that the point is on. Then, you count the amount of spaces horizontally it takes you to reach the point. In this problem, you move up 13 spaces, and move to the right 10 spaces. This as a fraction will be 13 over 10, because we rose 13 spaces and we ran 10 spaces to get to our second point. The y-intercept will be the only number that is on the y-axis, which is 2.

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Suppose a random sample of 100 observations from a binomial population gives a value of pˆ = .63 and you wish to test the null h

irakobra [83]

Answer:

We conclude that the population proportion is equal to 0.70.

Step-by-step explanation:

We are given that a random sample of 100 observations from a binomial population gives a value of pˆ = 0.63 and you wish to test the null hypothesis that the population parameter p is equal to 0.70 against the alternative hypothesis that p is less than 0.70.

Let p = population proportion.

(1) The intuition tells us that the population parameter p may be less than 0.70 as the sample proportion comes out to be less than 0.70 and also the sample is large enough.

(2) So, Null Hypothesis, $H_0$ : p = 0.70 {means that the population proportion is equal to 0.70}

Alternate Hypothesis, $H_A$ : p < 0.70 {means that the population proportion is less than 0.70}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion = 0.63

n = sample of observations = 100

So, the test statistics = $\frac{0.63-0.70}{\sqrt{\frac{0.70(1-0.70)}{100} } }$

= -1.528

The value of z-test statistics is -1.528.

Now at 0.05 level of significance, the z table gives a critical value of -1.645 for the left-tailed test.

Since our test statistics is more than the critical value of z as -1.528 > -1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the population proportion is equal to 0.70.

(c) The observed level of significance in part B is 0.05 on the basis of which we find our critical value of z.

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Natasha2012 [34]

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