In geometry, it would be always helpful to draw a diagram to illustrate the given problem.
This will also help to identify solutions, or discover missing information.
A figure is drawn for right triangle ABC, right-angled at B.
The altitude is drawn from the right-angled vertex B to the hypotenuse AC, dividing AC into two segments of length x and 4x.
We will be using the first two of the three metric relations of right triangles.
(1) BC^2=CD*CA (similarly, AB^2=AD*AC)
(2) BD^2=CD*DA
(3) CB*BA = BD*AC
Part (A)
From relation (2), we know that
BD^2=CD*DA
substitute values
8^2=x*(4x) => 4x^2=64, x^2=16, x=4
so CD=4, DA=4*4=16 (and AC=16+4=20)
Part (B)
Using relation (1)
AB^2=AD*AC
again, substitute values
AB^2=16*20=320=8^2*5
=>
AB
=sqrt(8^2*5)
=8sqrt(5)
=17.89 (approximately)
Answer:
Step-by-step explanation:
hello :
The expression 1/2mv^2
M=1.6x10^3
V=3.4x10^3
is : 1/2(1.6x10^3 )(3.4x10^3)²=2.72x 10^9
Answer:
Height of triangle = 16 meter
Step-by-step explanation:
Given:
Area of given triangle = 96 squares meter
Base length of triangle = 12 meter
Find:
Height of triangle
Computation:
Area of triangle = (1/2)(b)(h)
Area of given triangle = (1/2)(Base length of triangle)(Height of triangle)
96 = (1/2)(12)(Height of triangle)
96 = (6)(Height of triangle)
Height of triangle = 96 / 6
Height of triangle = 16 meter
Answer:
y + 4 = -2(x - 3)
Step-by-step explanation:
Use the point-slope formula y - k = m(x - h). Substitute -2 for k and 3 for h, as well as -2 for m:
y + 4 = -2(x - 3).