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Zina [86]
3 years ago
12

The odds of winning a teddy bear are 5:8. The probability of winning a framed picture is 43%. For which do you have a better cha

nce of winning?
Mathematics
1 answer:
Serhud [2]3 years ago
4 0

Answer:

I'd say you had a better chance going 5:8

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Write the sentence as an inequality. The cost of a ticket t will be no more than $52.
NeX [460]

Answer:

t is less than or equal to $52, or t <= $52

Step-by-step explanation:

If you can't have more than $52, then use less than symbol (<). The sentence doesn't state that a ticket shouldn't cost $52, so it's safe to assume that you can have exactly $52.

5 0
3 years ago
Any gírl here<br>.<br>.<br>.<br>.<br>let's chàt​
Rufina [12.5K]

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uhm no stop this is an app for people and work so please go

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2 years ago
Er the given circle.
nataly862011 [7]

Answer:

Step-by-step explanation:

answers

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3 0
3 years ago
How many solutions do these equations have
Arlecino [84]

Answer:

\large\boxed{\bold{one\ solution}\ (1,\ -4)\to x=1,\ y=-4}

Step-by-step explanation:

\left\{\begin{array}{ccc}y=2x-6\\y=-x-3\end{array}\right\\\\\text{These are linear functions. We only need two points to draw a graph.}\\\\\text{Choice two values of x, substitute to the equation,}\\\text{and calculate the values of y.}\\\\y=2x-6\\for\ x=0\to y=2(0)-6=0-6=-6\to(0,\ -6)\\for\ x=3\to y=2(3)-6=6-6=0\to(3,\ 0)\\\\y=-x-3\\for\ x=0\to y=-0-3=0-3=-3\to(0,\ -3)\\for\ x=-3\to y=-(-3)-3=3-3=0\to(-3,\ 0)\\\\\text{Look at the picture}

\text{The intersection of the line is the solution of the system of equations:}\\\\(1,\ -4)\to x=1,\ y=-4

7 0
3 years ago
HELLPPP????? PLEASEEEESSSS
Verdich [7]

Answer:

\boxed{43.48 \, \%}

Step-by-step explanation:

The formula for calculating percentage is

\text{Percentage} = \dfrac{\text{Part }}{\text{Whole}} \times 100 \, \%

The "part" is the number of single-shot espressos

The "whole" is the total number of espressos.

\begin{array}{rcl}\text{Total espressos} & = & 46\\\text{-Single-shot espressos} & = & 26\\\text{Double-shot espressos} & = & 20\\\end{array}

\text{ \% Double-shot}=\dfrac{20}{46} \times 100 \, \% =\mathbf{43.48 \, \%}\\\\\boxed{\mathbf{43.48 \, \%}} \text{ of the espressos were double-shot}

8 0
4 years ago
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