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nirvana33 [79]
3 years ago
14

Explain how you would find 36 x 3/4 mentally

Mathematics
2 answers:
borishaifa [10]3 years ago
7 0
Ok so first what you need to do is think about the question because this is a very simple question to understand and as they say nothing in this world is easy so you have to think about it and once you think about it and understand what they are asking you then you could solve and its very simple. 1st you have to follow order of operations which PEMDAS and I think you should be familiar using this strategy because I am very accoustomed to it and you should be as well, anyway, first do multiplication because in PEMDAS the m comes before the d which stands for division. So do 36x3 which is 108 and now we could do the final step which is to divide our product, 108, by 4 and the quotient shall be 27 as our final answer. So hope this helped you out and if it did than awesome and thank you for the question by the way so keep on asking questions!!
Alborosie3 years ago
6 0
36×3/4
we will simplify it in four's table
9×3=27
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A line has an c intercept of 3 and a y intercept of negative 6. What is the slope intercept form of it’s equation
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Answer:

y = 2x - 6

Step-by-step explanation:

Slope-intercept form is  y = mx + b, where m is the slope and b is the y-intercept.

The y-intercept is already given and is -6.

By c intercept, I am assuming you meant x-intercept.  With an x-intercept of 3, the point is (3,0).  With a y-intercept of -6, the point is (0,-6).

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m=\frac{y_{2}-y_{1}  }{x_{2}- x_{1} }

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8 0
3 years ago
Here is the region of integration of the integral Integral from negative 6 to 6 Integral from x squared to 36 Integral from 0 to
Soloha48 [4]

Answer:

a) ∫_{-6}^{6} ∫_{0}^{36} ∫_{x²}^{36} (-y) dy dz dx

b)  ∫_{0}^{36} ∫_{-6}^{6} ∫_{x²}^{36} (-y) dy dx dz

c)  ∫_{0}^{36} ∫_{x²}^{36} ∫_{-6}^{6} (-y) dx dy dz

e) ∫_{x²}^{36} ∫_{-6}^{6} ∫_{0}^{36} (-y) dz dx dy

Step-by-step explanation:

We write the equivalent integrals for given integral,

we get:

a) ∫_{-6}^{6} ∫_{0}^{36} ∫_{x²}^{36} (-y) dy dz dx

b)  ∫_{0}^{36} ∫_{-6}^{6} ∫_{x²}^{36} (-y) dy dx dz

c)  ∫_{0}^{36} ∫_{x²}^{36} ∫_{-6}^{6} (-y) dx dy dz

e) ∫_{x²}^{36} ∫_{-6}^{6} ∫_{0}^{36} (-y) dz dx dy

We changed places of integration, and changed boundaries for certain integrals.

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Artyom0805 [142]
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<span>5x-x=16.   4x=16   x=4 
</span>
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