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nirvana33 [79]
3 years ago
14

Explain how you would find 36 x 3/4 mentally

Mathematics
2 answers:
borishaifa [10]3 years ago
7 0
Ok so first what you need to do is think about the question because this is a very simple question to understand and as they say nothing in this world is easy so you have to think about it and once you think about it and understand what they are asking you then you could solve and its very simple. 1st you have to follow order of operations which PEMDAS and I think you should be familiar using this strategy because I am very accoustomed to it and you should be as well, anyway, first do multiplication because in PEMDAS the m comes before the d which stands for division. So do 36x3 which is 108 and now we could do the final step which is to divide our product, 108, by 4 and the quotient shall be 27 as our final answer. So hope this helped you out and if it did than awesome and thank you for the question by the way so keep on asking questions!!
Alborosie3 years ago
6 0
36×3/4
we will simplify it in four's table
9×3=27
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A vehicle travels a distance of 5t^4-10t^2+6 miles in t+2 minutes. What is the vehicles speed in miles/minutes?
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A number is multiplied by 3. If 1 is added to<br> the product, you get 4. What is the number?
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7 0
3 years ago
Mr. Good Wrench advertises that a customer will have to wait no more than 30 minutes for an oil change. A sample of 26 oil chang
Andru [333]

Answer:

The 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population standard deviation is:

CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}

The information provided is:

<em>n</em> = 26

<em>s</em> = 4.8 minutes

Confidence level = 90%

Compute the critical values of Chi-square as follows:

\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.10/2, (26-1)}=\chi^{2}_{0.05, 25}=37.652

\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.10/2, (26-1)}=\chi^{2}_{0.95, 25}=14.611

*Use a Chi-square table.

Compute the 90% confidence interval for the population standard deviation waiting time for an oil change as follows:

CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}

     =\sqrt{\frac{(26-1)\times 4.8^{2}}{37.652}}\leq \sigma\leq \sqrt{\frac{(26-1)\times 4.8^{2}}{14.611}}\\\\=3.9113\leq \sigma\leq 6.2787\\\\\approx 3.9 \leq \sigma\leq6.3

Thus, the 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

3 0
3 years ago
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