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4 years ago

(x^2-3x)^2-38(x^2-3x)-80 factor

Mathematics

1 answer:

Dominik [7]4 years ago

8 0

I hope this helps you

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You are a contractor and charge 45$ for a site visit plus an additional 24$ per hour for each hour you spend working on the site

arsen [322]

The equation relating this should be linear since the increase in amount earned is constant throughout which is $24 per hour. The equation is in the form:

y = mx + b

where,

y = earning

m = slope or earning per hour = $24

x = total number of hours

b = y intercept or initial earning upon visit = $45

Hence,

y = 24x + 45

Since we are working at two separate work sites, therefore each site we must earn 810/2 = 405

So when y = 405:

405 = 24x + 45

x = 15 hours

So you must work 15 hours at each site, 30 in total.

6 0

2 years ago

Use the following table to determine P(X≤3).

DiKsa [7]

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$P(x \leqslant 3) = P(1) + P(2) + P(3) \\$

$P(x \leqslant 3) = 0.25 + 0.32 + 0.17 \\$

$P(x \leqslant 3) = 0.74$

Thus the correct answer is

the last option .

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5 0

3 years ago

In the number below, what happens to the value of the digit 3 when it is moved one place value to the left?

Elis [28]

Answer:

it increases by a factor of 10, hence option B is the answer

Step-by-step explanation:

Initial Figure = 2037

When it is moved one place to the left, it increases from tens to hundreds

Hence option B is the answer

5 0

3 years ago

Express 0.456 as a percent

nordsb [41]

<span>Express 0.456 as a percent
=
45.6%

hope it helps</span>

3 0

3 years ago

Read 2 more answers

Recall the equation for a circle with center (h,k) and radius r. At what point in the first quadrant does the line with equation

IgorC [24]

Answer:

At intersection

x=2.68

y=5.34

Step-by-step explanation:

Equation of circle with center (h,k) and radius r is

$(x-h)^{2}+(y-k)^{2}=r^2\\\\With\,\, center\,\,(0,4)\,\, and\,\, r=3\\\\(x-0)^{2}+(y-4)^{2}=3^2\\\\x^2+(y-4)^{2}=9---(1)\\\\Equation\,\,of intersecting\,\,line\\y=0.5x+4---(2)$

To find point of intersection:

From (2)

$x=\frac{y-4}{0.5}=2(y-4)\\\\x^2=4(y-4)^{2}\\\\Put\,\,in\,\,(1)\\\\4(y-4)^{2}+(y-4)^{2}=9\\\\5(y-4)^{2}=9\\\\y-4=\frac{3}{\sqrt{5}}\\\\y=1.34+4\\\\y=5.34\\\\x=2(5.34-4)\\\\x=2(0.34)\\\\x=2.68$

At intersection

x=2.68

y=5.34

This point of intersection can be checked in graph attached below

3 0

3 years ago