Can you take a picture of the problem
The points of the graph are> (1,1), (2,2), (3,4), (4,8).
Then the sequence is:
- for the x-coordinate: 1, 2, 3, 4, 5, 6, 7, ...
- for the y-coordinate: 1, 2, 4, 8, which is: 2^0, 2^1, 2^2, 2^ 3, ... so the next y-coordinates are 16, 32, 64, 128, ...
So, the sequence is: 1, 2, 4, ,8, 16, 32, .... 2^x.
<h3>
Answer: 42</h3>
Explanation:
We have y = -0.9x^2 + 76x - 250 which is in the form y = ax^2+bx+c
where,
The vertex (h,k) is when the profit is maxed out.
h = -b/(2a)
h = -76/(2(-0.9))
h = 42.222 approximately
Let's plug in x values around x = 42
Try x = 41
y = -0.9x^2 + 76x - 250
y = -0.9(41)^2 + 76(41) - 250
y = 1353.10
Now try x = 42
y = -0.9x^2 + 76x - 250
y = -0.9(42)^2 + 76(42) - 250
y = 1354.4
Now try x = 43
y = -0.9x^2 + 76x - 250
y = -0.9(43)^2 + 76(43) - 250
y = 1353.9
We see that the largest profit happens when x = 42.
Answer:
D
Step-by-step explanation:
Answer:
B), x=-1, y=-2, z=1.
Step-by-step explanation:
