Invested amount (P0 = £6000.
Rate of interest (r) = 3.4% = 0.034.
We know compound interest formula
A = P(1+r)^t
We need work out the value of his investment per year.
So, we need to plug t=1 and plugging values of P and r in the formula above, we get
A = 6000(1+0.034)^1
A = 6000(1.034)
A = 6204.
<h3>Therefore, the value of his investment per year is £ 6204.</h3>
Now, we need to work out the value of his investment after 3 years.
So, we need to plug t=3.
A = 6000(1+0.034)^3
A = 6000(1.034)^3
1.034^3=1.105507304
A = 6000 × 1.105507304
A = 6633.04
<h3>Therefore, the value of his investment after 3 year is £ 6633.04.</h3>
The answer is $.085. This is the cost of the gasoline per mile. I got the answer through adding all the expenses (insurance, registration, and maintenance) which added up to $1191 and then subtracting it from $1837, which gets me $646. Lastly, I computed for the cost of gasoline per mile through dividing $646 by 7600 miles. I got .085.
Answer:

Step-by-step explanation:
1) Use FOIL method: (a + b) (c + d) = ac + ad + bc + bd.

2) Collect like terms.

3) Simplify.

<em><u>Therefor</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><u>x</u><u>²</u><u> </u><u>+</u><u> </u><u>9x</u><u> </u><u>+</u><u> </u><u>20</u>.
Answer:
Option B)
is the correct option.
Step-by-step explanation:
<em>Exponential function is the one where, a constant is raised to the power of x, a independent variable.</em>
Here, only option B and D are such exponential functions, while option A is linear and option C is quadratic in nature.
Now, to verify which option is correct, we will input the values and check which has the least difference between the given values.
Or we can use the cost function,
, to find which function has the least error.
By applying the above results,we find Option B is correct.
Answer: 12
Step-by-step explanation: