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3 years ago

Can anyone help me with this please :( . Don’t answer if you do not know

Mathematics

2 answers:

suter [353]3 years ago

7 0

Answer:

the answer should be c. have a grand one

Ipatiy [6.2K]3 years ago

7 0

Answer: C

Step-by-step explanation:

Remember that the y-axis is going up by 100s so we can strike off A and D. What I did is looked for a point at an intersecting grid line. I looked at the point (3,4) this means after 3 years, 400 people have joined. Then I divided 400 by 3 and got 133, therefore your answer is C

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A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0

3 years ago

The number of feet in i inches

joja [24]

If you mean 1 insted of i it would be a 1/12 or a twelef
I believe that I spelt some words wrong so double check

7 0

4 years ago

Factorize 1) x²-4y² 2) 27-8y³

HACTEHA [7]

you cant factorise both of them as they have nothing in common

8 0

3 years ago

Find the zeros of the polynomial 99x + 11. O-1/9 O 1/9 O 9 O-9

ICE Princess25 [194]

Answer:

-1/9

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The perimeter of a rectangle is 72 cm. The length is 3 more than twice the width What

solmaris [256]

<h3>Solution</h3>

Given :-

Perimeter of rectangle = 72 cm
The length is 3 more than twice the width.

Find :-

Dimensions of rectangle

<h3 /><h3>Explantion</h3>

Using Formula

$\boxed{\underline{\tt{\red{\:(perimeter_{rectang}\:=\:2\times (Length+Width)}}}}$

Let,

Length of Rectangle = x cm
Breadth of Rectangle = y cm

According to question,

==> perimeter of Rectangle = 72

==> 2(x+y) = 72

==> x + y = 72/2

==> x + y = 36_________________(1)

Again,

==> x = 2y + 3

==> x - 2y = 3__________________(2)

Subtract equ(1) & equ(2)

==> y + 2y = 36 - 3

==> 3y = 33

==> y = 33/3

==> y = 11

keep in equ(1)

==> x - 2×11 = 3

==> x = 3 + 22

==> x = 25

<h3>Hence</h3>

Length of Rectangle = 25 cm
Width of Rectangle = 11 cm

<h3 />

7 0

3 years ago