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4 years ago

Solve the following absolute value equation.

Mathematics

1 answer:

Ivanshal [37]4 years ago

7 0

So the equation is 2[x + 1] = 6, right? So you’d solve it as follows:

2[x + 1] = 6

Divide both sides by 2

[x + 1] = 3

Subtract one to get x by itself

[x] = 2

If x is 2, then the absolute value of x is the absolute value of 2. The absolute value of 2 is 2 and -2

X = 2 or -2

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Does anyone understand how to do this? im stuck

Alina [70]

Dy/dx = y/x^2
1/y dy = 1/x^2 dx
int(1/y dy) = int(1/x^2 dx)
ln y + c1 = -x + c2
ln y = -x + c ; c= c2-c1
y = e^(-x+c) = e^c e^-x
y = Ce^-x ; C=e^c

8 0

3 years ago

What is (4x + 3) + (-2x + 4)

kobusy [5.1K]

Answer:

(4x + 3) + (-2x + 4) = 2x + 7

Step-by-step explanation:

(4x + 3) + (-2x + 4) = you then collect like terms

(4x + -2x) + (3 + 4)= like this, and you add what's inside perenthesis

= 2x + (3 + 4). step-by-step

= 2x + 7. then that is how you get =2x+7

5 0

3 years ago

Read 2 more answers

An agency is studying the income of store managers in the retail industry. A random sample of 25 managers reveals a sample mean

aalyn [17]

Answer:

The Confidence Interval = ($44,745.55 , $46,094.45)

Step-by-step explanation:

The formula for Confidence Interval =

Confidence Interval = Mean ± z × Standard deviation/√n

Where n = number of samples = 25 managers

Standard deviation = $2,050

Mean = $45,420

z = z score of the given confidence interval

= z score of 90% confidence interval

= 1.645

Confidence Interval = $45,420 ± 1.645 × $2,050/√25

= $45,420 ± 1.645 × $2,050/5

= $45,420 ± 674.45

Confidence Interval =

$45,420 - 674.45 = $44,745.55

$45,420 + 674.45 = $46,094.45

Therefore, the Confidence Interval = ($44,745.55 , $46,094.45)

3 0

3 years ago

Can somebody help me with this

LekaFEV [45]

Probability = option(s) that we want / total number of possibilities

Options that we want = cash or credit card = 50 + 4 = 54

Total number of possibilities = cash, debit card, credit card = 50 + 2 + 4 = 56

54 / 56 = 0.96

Answer: 0.96

Hope this helps!

5 0

3 years ago

A rectangle with an area of 24 square units has length x+1 and width 4x-6. find the value of x.

dimulka [17.4K]

$area = length \cdot width \\ \\A = 24 s^2 \\ \\ l=x+1 , \ \ w=4x-6 \\ \\ A=lw\\ \\24 =(x+1)(4x-6)$

$24 =4x^2-6x+4x-6 \\ \\4x^2-6x+4x-6 -24=0\\ \\4x^2-2x-30=0 \ \ / :2\\ \\2x^2-x-15=0 \\ \\a=2, \ b=-1 , c= -15$

$\Delta =b^2-4ac = (-1)^2 -4\cdot2\cdot (-15) = 1+120=121\\ \\x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{1-\sqrt{121}}{2*2 }=\frac{ 1-11}{4}=\frac{-10}{4}=- \frac{5}{2} \\ \\x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{1+\sqrt{121}}{2*2 }=\frac{ 1+11}{4}=\frac{12}{4}=3 \\ \\Use \ positive \ value \ of \ x : \\ \\ x =3$

5 0

4 years ago