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Kryger [21]
3 years ago
10

Yal come on help me pls help me

Mathematics
2 answers:
vlabodo [156]3 years ago
7 0

Answer:

X

Step-by-step explanation:

DENIUS [597]3 years ago
6 0
The answer is x Im pretty sure
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How do You graph : y-10= -5x?
miv72 [106K]

Equation:

y - 10 = -5x

Solve:

(y - 10) + 10 = (-5x) + 10

y = -5x + 10

Remember the formula (Slope Intercept Form):

y = mx + b

m = Slope (Rise/Run)

b = Y-intercept

So your graph would look something like the attached image:

<em>(Need further elaboration? Let me know!)</em>

5 0
3 years ago
Answer me pleaseeee..... prime numbers between 1 to 10 ?​
My name is Ann [436]

Answer:

2, 3, 5, 7

Step-by-step explanation:

prime numbers between 1 to 10 are 2,3,5,7. it's very easy. 1 is not prime number because it behave as both prime and composite.

8 0
2 years ago
Solve the equation <br><br> 3x-1/2y=2
poizon [28]

Answer:

Step-by-step explanation:

Without a second equation relating x and y, we can solve 3x - 1/2y = 2 ONLY for x in terms of y or for y in terms of x:

x in terms of y:    Multiply all three terms of 3x - 1/2y = 2 by 2, to eliminate the fraction:  6x - y = 4.  Now add y to both sides to isolate 6x:  6x = 4 + y.

Last, divide both sides by 6 to isolate x:

x = (4 + y)/6

y in terms of x:    

y = 6x - 4

If you want a numerical solution, please provide another equation in x and y and solve the resulting system.

4 0
3 years ago
The weight of baby goats is believed to be Normally distributed, with a mean of 5.75 pounds. The average weight of a random samp
Julli [10]

Answer:

The standard error of the mean is 0.0783.

Step-by-step explanation:

The Central Limit Theorem helps us find the standard error of the mean:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

The standard deviation of the sample is the same as the standard error of the mean. So

SE_{M} = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\sigma = 0.35, n = 20

So

SE_{M} = \frac{\sigma}{\sqrt{n}}

SE_{M} = \frac{0.35}{\sqrt{20}}

SE_{M} = 0.0783

The standard error of the mean is 0.0783.

7 0
3 years ago
What is the value of f(-4)
WITCHER [35]

Answer:

7

Step-by-step explanation:

Substitute x = -4 :

f(-4) =  3 - (-4)

= 3 + 4

= 7

4 0
3 years ago
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