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pickupchik [31]
3 years ago
7

Which of the following represents the correct inequality statements

Mathematics
1 answer:
mezya [45]3 years ago
6 0

Answer:

what are the options to the question

Step-by-step explanation:


You might be interested in
Use the picture attached.
Annette [7]

Answer: look honestly I am not sure but Probably it is choice c which is 2 lines of symmetry .

Step-by-step explanation: 2 lines of symmetry because one line is horizontal and the other is vertical . One line will be in the middle of the flower which is vertical and the other line is horizontal as they will make equivalent sides . HOPE IT HELPS BUDDY .

7 0
2 years ago
Find the number of positive integers n is less than or equal to 1000 such that 15n is a perfect square.
boyakko [2]

Answer:

8 positive integers.

Step-by-step explanation:

One value of n would be 15 because 225 = 15^2.

Other values  are 225 * n where 15n  <= 1000 and n is a perfect square.

So n = 4 gives us 225* 4 = 900 which is a perfect square and 15*4 = 60.

n = 9  gives us 225 * 9 which is a perfect square and 15*9 = 135.

n = 16 gives us 225*16  and 15*16 = 240 , so OK.

n = 25   gives a perfect square and  and 15*25 = 375 - so OK.

n = 36 gives a perfect square and 15*36 = 540 - so OK.

n = 49 gives a perfect square and  15*49 = 735 - so OK.

n = 64 gives a perfect square and 15*64 = 960 - so ok.

n = 81 gives a perfect square and 15 * 81 = 1215  so NOT ok.

3 0
3 years ago
Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean
Zinaida [17]

Answer:

E[R] = 99 Ω

\sigma_R = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, E[R] = \frac{a+b}{2}  = \frac{95+103}{2} = \frac{198}{2} = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333

Hence,

The standard deviation of resistance, \sigma_R = \sqrt{V(R)} = \sqrt5.333 = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

z_1 = \frac{102-99}{2.3094} = 1.299

z_2 = \frac{98-99}{2.3094} = -0.433

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0
3 years ago
3A + 4N - 5A + 3 - 8N + 11 =
Anit [1.1K]

Answer:

-2a-4n+14

Step-by-step explanation:

7 0
3 years ago
Solve the inequality. 22−2x&lt;38 Which answer represents the solution set?
algol [13]

Answer:

x >-8

Step-by-step explanation:

22−2x<38

Subtract 22 from each side

22-22−2x<38-22

-2x < 16

Divide each side by -2, remembering to flip the inequality

-2x/-2 > 16/-2

x >-8

3 0
3 years ago
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