What are the solutions of 4x2 - 16X = 16x - 39
1 answer:
Answer:
x = , x =
Step-by-step explanation:
Given
4x² - 16x = 16x - 39 ( subtract 16x - 39 from both sides )
4x² - 32x + 39 = 0
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term, that is
product = 4 × 39 = 156 and sum = - 32
The factors are - 26 and - 6
Use these factors to split the x- term
4x² - 26x - 6x + 39 = 0 ( factor the first/second and third/fourth terms )
2x(2x - 13) - 3(2x - 13) = 0 ← factor out (2x - 13) from each term
(2x - 13)(2x - 3) = 0
Equate each factor to zero and solve for x
2x - 3 = 0 ⇒ 2x = 3 ⇒ x =
2x - 13 = 0 ⇒ 2x = 13 ⇒ x =
You might be interested in
The vertex is at (0, 3) so y=a(x-0)²+3, which is y=ax²+3
next, use a given point to find a: 10=a(3)²+3, so 9a=7, a=7/9
the equation is then y=
as for the first question, the shape is an ellipse, the domain is -5≤x≤5, the range is -3≤y≤3
the equation can be written as :
next, use a given point to find a: 10=a(3)²+3, so 9a=7, a=7/9
the equation is then y=
as for the first question, the shape is an ellipse, the domain is -5≤x≤5, the range is -3≤y≤3
the equation can be written as :