Answer:
The area is 
Step-by-step explanation:
I assume that the figure is a square
The area of a square is equal to
where
b is the length side of the square
In this problem we have
substitute in the formula
Factor:
3x^2 + 27
= 3(x^2 + 9)
Answer is 3(x^2 + 9), when factored.
A) (3x + 9i)(x + 3i)
= (3x + 9i)(x + 3i)
= (3x)(x) + (3x)(3i) + (9i)(x) + (9i)(3i)
= 3x^2 + 9ix + 9ix + 27i^2
= 27i^2 + 18ix + 3x^2
B) (3x - 9i)(x + 3i)
= (3x + - 9i)(x + 3i)
= (3x)(x) + (3x)(3i) + ( - 9i)(x) + (- 9i)(3i)
= 3x^2 + 9ix - 9ix - 27i^2
= 27i^2 + 3x^2
C) (3x - 6i)(x + 21i)
= (3x + - 6i)(x + 21i)
= (3x)(x) + (3x)(21i) + (- 6i)(x) + ( -6i)(21i)
= 3x^2 + 63ix - 6ix - 126i^2
= - 126i^2 + 57ix + 3x^2
D) (3x - 9i)(x - 3i)
= (3x + - 9)(x + - 3)
= (3x)(x) + (3x)( - 3i) + (- 9)(x) + ( - 9)( - 3i)
= 3x^2 - 9ix - 9x + 27i
= 9ix + 3x^2 + 27i - 9x
Hope that helps!!!
Answer:
Given, two numbers 56 and 57 we need to find out the numbers lie between the squares of the given numbers.
Now, we have numbers lying between the square of n and (n + 1) is 2n
⇒ Numbers between squares of 56 and (56 + 1) = 2 × 56 = 112
Hence, 112 numbers lies between the square of the given numbers.
Answer: D
-2.9a+6.8+4.4a-7.3
[-2.9a+4.4a]=1.5a
[6.8-7.3]=-0.5
1.5a-0.5
