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2 years ago

Given the formula y = mx + b, what is the slope of a line, m, if x = 5, y = 7, and b =10?

1 answer:

3 0

The answer is:
C. The slope -3/5
Because -3/5 times 5 is -3 and when you combine -3 and 10 the answer is 7 and 7=7 (the y)

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5(-6-3d)=3(8+7d)(if there is no solution,type in ''no solution'')d= Answer

swat32

In this question, you're solving for d.

Solve for d:

5(-6 - 3d) = 3(8+7d)

Use the distributive property:

-30 - 15d = 3(8+7d)

-30 - 15d = 24 + 21d

Add 30 to both sides:

-15d = 54 + 21d

Subtract 21d from both sides

-36d = 54

Divide both sides by -36

d = -3/2

Answer:

d = -3/2 or -1.5

6 0

2 years ago

Read 2 more answers

Which of the following statements are the same? (A) x -= x + 4 (B) x = x + 4 - x (C) x = x - (x + 4) (A) and (B) are the same (A

Nesterboy [21]

Answer: (A) and (B) are the same

Step-by-step explanation:

for (A)

x-=x+4

x=x-(x+4)

x=x-x-4

x=4

for (B)

x=x+4-x

x=4

for (C)

x=x-(x+4)

x=x-x-4

x=-4

so (A) and (B) are the same because the value of their x is +4

5 0

3 years ago

Matthew scored a total of 168 points this basket ball season. He scored 147 of those points in the regular season, and the rest

Ksivusya [100]

$\frac{147}{168} = \frac{x}{100}$
147×100=14700
168×x=168x
14700÷168=87.5
100-87.5=12.5
Your answer is 12.5 percent of it were earned during the playoffs. Hope I was helpful.

6 0

3 years ago

You have just completed an experiment measuring the length (in mm) of 12 soybean plants after 3 days of sprouting. The measureme

sweet-ann [11.9K]

Answer:

The new IQR is 22.

Step-by-step explanation:

We are given the following data of length (in mm) of 12 soybean plants after 3 days of sprouting.

53, 47, 51, 54, 43, 39, 61, 57, 55, 46, 44, 43

Sorted data:

39, 43, 43, 44, 46, 47, 51, 53, 54, 55, 57, 61

Formula:

$IQR = Q_3 - Q_1\\Q_3 = \text{upper median},\\Q_1 = \text{ lower median}$

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$