Answer:
The area of the patio is 43 square feet
Step-by-step explanation:
In this question, we have a trapezoid and we are asked to calculate the area of the patio which is in the form of the trapezoid.
Please check attachment for possible trapezoid picture.
Mathematically, the area of the trapezoid can be calculated using the mathematical formula below;
A = 1/2 (a+b) h
where a and b are the lengths of the parallel sides.
Now, let’s say a is 17 feet
b was stated explicitly to be 2 feet half the length of the longer base. That would be 1/2(17) - 2 = 8.5 -2 = 6.5 feet
Now let’s calculate the area of the patio;
A = 1/2(6.5+17) * 4 = 2(23.5) = 47 square feet
Answer:
mABC = 110
Step-by-step explanation:
Answer:
Total = 2,500 (1.021)^t
Step-by-step explanation:
There is no question but the formula for compound interest is
Total = amount (1 + rate)^time
Total = 2,500 (1.021)^t
Answer:
2
Step-by-step explanation:
are you siruous
Answer:
Therefore the value of x is
![x=1\pm\sqrt{19}i](https://tex.z-dn.net/?f=x%3D1%5Cpm%5Csqrt%7B19%7Di)
Step-by-step explanation:
Given:
which is
![x^{2}-2x+20=0](https://tex.z-dn.net/?f=x%5E%7B2%7D-2x%2B20%3D0)
To Find:
x = ? using Quadratic Formula
Solution:
For a Quadratic Equation ax² + bx + c = 0 , Formula Method is given as
![x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B-b%5Cpm%5Csqrt%7Bb%5E%7B2%7D-4ac%7D%7D%7B2a%7D)
On Comparing with above we get
![a=1\\b=-2\\c=20](https://tex.z-dn.net/?f=a%3D1%5C%5Cb%3D-2%5C%5Cc%3D20)
Substituting a , b , c in Formula method we get
![x=\dfrac{-(-2)\pm\sqrt{(-2)^{2}-4(1)(20)}}{2\times 1}\\\\x=\dfrac{2\pm\sqrt{-76}}{2}\\\\x=\dfrac{2\pm2\sqrt{19}i}{2}\\Dividing\ by\ 2\ we\ get\\\\x=1 \pm\sqrt{19}i](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B-%28-2%29%5Cpm%5Csqrt%7B%28-2%29%5E%7B2%7D-4%281%29%2820%29%7D%7D%7B2%5Ctimes%201%7D%5C%5C%5C%5Cx%3D%5Cdfrac%7B2%5Cpm%5Csqrt%7B-76%7D%7D%7B2%7D%5C%5C%5C%5Cx%3D%5Cdfrac%7B2%5Cpm2%5Csqrt%7B19%7Di%7D%7B2%7D%5C%5CDividing%5C%20by%5C%202%5C%20we%5C%20get%5C%5C%5C%5Cx%3D1%20%5Cpm%5Csqrt%7B19%7Di)
Therefore the value of x is
![x=1\pm\sqrt{19}i](https://tex.z-dn.net/?f=x%3D1%5Cpm%5Csqrt%7B19%7Di)