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3 years ago

Which triangle congruence postulate, if any, can be used to prove the two triangles are congruent

Mathematics

1 answer:

xxMikexx [17]3 years ago

7 0

Answer:

dont know answer sorry minsan tama na sagot

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PLEASE HELP WILL GIVE THANKS AND FIVE STARS IF RIGHT ANSWER

Vika [28.1K]

(x+4)^2 / 9 - (y+3)^2 / 16 = 1

a^2 = 16 and b^2 = 9

a = +4 and -4

b = +3 and -3

Center is (-4, -3)

Vertices is (-4 + a, -3) and (-4 - a, -3)

Vertices is (-1, -3) and (-7, -3)

8 0

3 years ago

Can someone help me with this please idk if it’s the right answer

hram777 [196]

Answer:

x = 2

Step-by-step explanation:

5x + (x + 12)

6x = 12

x = 2

3 0

3 years ago

156 is even or odd number

Scrat [10]

156 is even or odd number
Even number, it is divisible by 2

6 0

3 years ago

Write a plan to prove that ∠1≅∠2.

inn [45]

Answer:

∠1≅∠2

Step-by-step explanation:

Because 2 is 1 number more, they are approximitly the same:)

3 0

3 years ago

Read 2 more answers

NEED HELP ASAP 30 POINTS WILL BE GIVEN TO BRAINLIEST

WINSTONCH [101]

we know that

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

$G(-1,3)\ H(1,2)\ J(-3,-1)$

Step 1

Find the slope GH

$G(-1,3)\ H(1,2)$

substitute in the formula

$m=\frac{2-3}{1+1}$

$m=\frac{-1}{2}$

$mGH=-\frac{1}{2}$

Step 2

Find the slope HJ

$H(1,2)\ J(-3,-1)$

substitute in the formula

$m=\frac{-1-2}{-3-1}$

$m=\frac{-3}{-4}$

$mHJ=\frac{3}{4}$

Step 3

Find the slope JG

$J(-3,-1)\ G(-1,3)$

substitute in the formula

$m=\frac{3+1}{-1+3}$

$m=\frac{4}{2}$

$mJG=2$

Step 4

Verify if triangle GHJ is a right triangle

we know that

if two lines are perpendicular, then the product of their slopes is equal to minus one

$m1*m2=-1$

compare slope GH with slope JG

we have

$mGH=-\frac{1}{2}$

$mJG=2$

$-\frac{1}{2}*2=-1$ -----> side GH and side JG are perpendicular

The triangle GHJ is a right triangle

The answer in the attached figure

4 0

3 years ago