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inna [77]
3 years ago
9

A dog groomer wants to gather information about how often dog owners have their dogs groomed. She decides to take

Mathematics
1 answer:
weeeeeb [17]3 years ago
6 0

Answer:

a systematic random sample

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Stack of wood 4 feet wide 8 feet long and 4 feet high is equal to 1 quart of wood. How many quarts would a pie 4 feet wide and 1
Semmy [17]

Answer:

2 quarts

Step-by-step explanation:

Since a stack of  wood 4 feet wide 8 feet long and 4 feet high is equal to 1 quart of wood., then dimensionally, we write it as 4 × 8 × 4.

We then need to find the number of quarts in a pie of 4 feet wide and 16 feet long and 4 feet high. We write it dimensionally as 4 × 16 × 4.

Since 1 quart = 4 × 8 × 4, then the number of quarts in 4 × 16 × 4 is

4 × 16 × 4 × 1 quart/4 × 8 × 4 = 2 × 1 quart = 2 quarts

6 0
3 years ago
Whats the area of a triangle with a base length of 3 units and a height of 4 units
WINSTONCH [101]

area =  1/2 x b x h

1/2 x 3 x 4 = 6 units

8 0
3 years ago
What are the solutions to the following system?
RoseWind [281]
\bf \begin{cases}
-2x^2+y=-5\\
\boxed{y}=-3x^2+5\\
----------\\
-2x^2+\left( \boxed{-3x^2+5} \right)=-5
\end{cases}
\\\\\\
-5x^2+5=-5\implies -5(x^2-1)=-5\implies x^2-1=\cfrac{-5}{-5}
\\\\\\
x^2-1=1\implies x^2=2\implies x=\pm\sqrt{2}

and since we know what "x" is, then let's substitute it on say the 1st equation

\bf -2x^2+y=-5\implies -2\left( \pm \sqrt{2} \right)^2+y=-5\implies -4+y=-5
\\\\\\
y=-1\\\\
-------------------------------\\\\
\left( \sqrt{2}~,~-1 \right)\qquad \left( -\sqrt{2}~,~-1 \right)
7 0
3 years ago
Read 2 more answers
A car has 15 gallons of gas in its tank. The car travels 35 miles per gallon of gas. It uses 1/35 of gas to go 1 mile. How much
3241004551 [841]

Answer:

um......I think 2 figure it out....

Step-by-step explanation:

A car has 15 gallons of gas in its tank. The car travels 35 miles per gallon of gas. It uses 1/35 of gas to go 1 mile.

6 0
3 years ago
Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software,
vichka [17]

Answer:

A(-1,0) is a local maximum point.

B(-1,0)  is a saddle point

C(3,0)  is a saddle point

D(3,2) is a local minimum point.

Step-by-step explanation:

The given function is  

f(x,y)=x^3+y^3-3x^2-3y^2-9x

The first partial derivative with respect to x is  

f_x=3x^2-6x-9

The first partial derivative with respect to y is  

f_y=3y^2-6y

We now set each equation to zero to obtain the system of equations;

3x^2-6x-9=0

3y^2-6y=0

Solving the two equations simultaneously, gives;

x=-1,x=3  and y=0,y=2

The critical points are

A(-1,0), B(-1,2),C(3,0),and D(3,2).

Now, we need to calculate the discriminant,

D=f_{xx}(x,y)f_{yy}(x,y)-(f_{xy}(x,y))^2

But, we would have to calculate the second partial derivatives first.

f_{xx}=6x-6

f_{yy}=6y-6

f_{xy}=0

\Rightarrow D=(6x-6)(6y-6)-0^2

\Rightarrow D=(6x-6)(6y-6)

At A(-1,0),

D=(6(-1)-6)(6(0)-6)=72\:>\:0 and f_{xx}=6(-1)-6=-18\:

Hence A(-1,0) is a local maximum point.

See graph

At B(-1,2);

D=(6(-1)-6)(6(2)-6)=-72\:

Hence, B(-1,0) is neither a local maximum or a local minimum point.

This is a saddle point.

At C(3,0)

D=(6(3)-6)(6(0)-6)=-72\:

Hence, C(3,0) is neither a local minimum or maximum point. It is a saddle point.

At D(3,2),

D=(6(3)-6)(6(2)-6)=72\:>\:0 and f_{xx}=6(3)-6=12\:>\:0

Hence D(3,2) is a local minimum point.

See graph in attachment.

3 0
3 years ago
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