Answer:
1+tan2x
Tan2x
= <u> sec²x </u> = <u>Sec²x </u> = cosec²x
Tan²x ( Sec²x/cosec²x)
Step-by-step explanation:
Answer:
Step-by-step explanation:
N = 3rt^4 - 5rz
now factor r out
N = r(3t^4-5z)
divide by r on both sides
N/r = (3t^4 - 5z)
subtract (3t^4)
N/r - 3t^4 = -5z
now divide by -5 to isolate the variable (z)
= z
Answer: Our required probability is 39.69%.
Step-by-step explanation:
Since we have given that
Probability of a bowler getting a strike during a particular frame = 63%
Number of frames are performed = 2
We need to find the probability that the bowler would be most likely to get a strike in each of the two frames.
So, it becomes,

Hence, Our required probability is 39.69%.