Speed of student A is 180 ft/min
Speed of student B is 120 ft/min
Relative speed=(120+180)=300 ft/min
Distance between them is 2420 ft
Time taken for them to meet will be:
time=distance/speed
=(2420-20)/300
=8 min
Answer:
-12p+p^2+36
Step by step explanation:
(-p+6)^2 is the square of -p+6
we use the formula
(a+b)^2=2ab+a^2+b^2
(-p+6)^2=-12p+p^2+36
the minus of p disappears
The value k = 5 will shift the parent function 5 units up. i.e. vertical shift of 5 units up.
