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3 years ago

The height of a rocket a given number of seconds after it is released is modeled by . What does t represent?

1 answer:

6 0

$\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \\\\ ~~~~~~\textit{in meters} \\\\ h(t) = -4.9t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases}$

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J____K_______L JK is x+3 KL is 2x-5 JL is 19 find the value of JK

charle [14.2K]

JK= 8, because x+3= 2x-5= 19

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3 years ago

What are the coordinates of the vertex of the parabola with the equation y = x + 2x - 3?

loris [4]

Answer:

The coordinates of the vertex are (-1,-4).

Step-by-step explanation:

Equation of the Quadratic Function

The vertex form of the quadratic function has the following equation:

$y-k=a(x-h)^2$

Where (h, k) is the vertex of the parabola that results when plotting the function, and a is a coefficient different from zero.

We are given the function:

$y=x^2+2x-3$

We must transform the equation above by completing squares:

The first two terms can be completed to be the square of a binomial. Recall the identity:

$x^2+2xy+y^2=(x+y)^2$

Thus if we add and subtract 1:

$y=(x^2+2x+1)-3-1$

Operating:

$y=(x^2+2x+1)-4$

The trinomial in parentheses is a perfect square:

$y=(x+1)^2-4$

Adding 4:

$y+4=(x+1)^2$

Comparing with the vertex form of the quadratic function, we have the vertex (-1,-4).

The coordinates of the vertex are (-1,-4).

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2 years ago

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torisob [31]

Answer:

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Step-by-step explanation:

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Dominik [7]

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Order the group of quadratic functions from widest to narrowest graph.

mr_godi [17]

Answer:Easy peasy lemon squeezy ahaha

Step-by-step explanation:

Vertex of g (6,23)

Axis of symmetry is 6

shift the graph right and up

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3 years ago