1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nikdorinn [45]
3 years ago
5

CAN SOMEONE PLEASE WRITE THIS OUT? 99 POINTS FOR THE ANSWE

Mathematics
2 answers:
kumpel [21]3 years ago
7 0
Natasha: 2x - 3
Elena: x

2x - 3 = 15
add 3 to both sides

2x = 18
divide both sides 2 to is plat the variable

x = 9

If Natasha stole 15 bases, then Elena stole 9.
Montano1993 [528]3 years ago
3 0
15 + 3 / 2 = 9.

Elena stole 9 bases.
You might be interested in
a study examined the effectiveness of an ear molding technique used to correct ear deformities in newborns without the need for
inna [77]

Answer:

The sample proportion of successful procedures is 0.962.

Step-by-step explanation:

The sample proportion of successful procedures is the number of successfiç procedures divided by the total number of procedures.

In this problem:

158 procedures, of which 152 were successful. So

p = 152/158 = 0.962

The sample proportion of successful procedures is 0.962.

4 0
3 years ago
A number cube is rolled and a letter is selected from the word BOOKCASE.
Deffense [45]

Answer: i need help on that too

Step-by-step explanation: i need helpppp

8 0
3 years ago
Asked what the central limit theorem says, a student replies, As you take larger and larger samples from a population, the histo
Arada [10]

Answer:

A. No, the student is not right. The central limit theorem says nothing about the histogram of the sample values. It deals only with the distribution of the sample means.

Step-by-step explanation:

No, the student is not right. The central limit theorem says nothing about the histogram of the sample values. It deals only with the distribution of the sample means. The central limit theorem says that if we take a large sample (i.e., a sample of size n > 30) of any distribution with finite mean \mu and standard deviation \sigma, then, the sample average is approximately normally distributed  with mean \mu and variance \sigma^2/n.

5 0
3 years ago
Simplify V45 fully, giving your answer in the form avb<br><br> What is the answer to this?
Sergeu [11.5K]

\textit{Hello There!}

\text{\underline{ANSWER:}}

=3\sqrt{5} .

\textit{Hopefully, this helps you!!}

\boxed{\text{AnimeVines}}

7 0
3 years ago
Read 2 more answers
6c-8-2c=-16+c what’s the value of c
Artemon [7]

Answer:

The correct answer is c = -8/3.

Step-by-step explanation:

The first step in solving this problem would be to simplify by combining like terms on the left side of the equation.

6c - 8 - 2c = -16 + c

4c - 8 = -16 + c

Then, we can subtract c from both sides of the equation to get rid of the positive c on the right side of the equation.

4c - c - 8 = -16 + c - c

3c - 8 = -16

Next, we can add 8 to both sides of the equation.

3c - 8 + 8 = -16 + 8

3c = - 8

Then, we can divide both sides of the equation by 3.

c = -8/3

Hope this helps!

7 0
3 years ago
Other questions:
  • Andre is setting up rectangular tables for a party. He can fit 6 chairs around a single table. Andre lines up 10 tables end-to-e
    12·1 answer
  • What’s the answer to this ?
    12·1 answer
  • What addition double fact can help you find 4+3
    12·2 answers
  • Hannas school her to the book donation there are 150 students at her school and they Donated a total of b books Hannah do need i
    14·1 answer
  • Can someone tell me the formulas for this​
    12·1 answer
  • 14. greater than a number g is 32​
    5·1 answer
  • Adrian has already earned $66 washing and waxing cars. He earns $9 per car. He wants to save at least $250 for a new
    5·1 answer
  • Is (1, 2) a solution to the inequality 6x - y&gt; 3?
    14·1 answer
  • How do i solve this proportion? 3t/10 = 1/2
    15·1 answer
  • X=<br> Help me please thanks
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!