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3 years ago

Is (1, 2) a solution to the inequality 6x - y> 3?

Mathematics

1 answer:

Lostsunrise [7]3 years ago

5 0

Answer:

Yes.

Step-by-step explanation:

To find the answer we will put it into the equation, since x = 1 and y = 2 we will write it like this, 6(1) - 2 > 3. Since 6 x 1 = 6, we will now subtract 6 from 2 which equals 4. Therefore, the equation is correct because 4 is bigger than 3.

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What is the sum of 16 quotient of 3

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X + y = 16 (1)
x/y = 3 (2)
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x + y = 16
x = 16 - y
1. Substitute x into equation 2
16-y/y = 3
16 - y = 3y
16 = 4y
y = 4
2. Now substitute y into equation 1
x/y = 3
x/4 = 2
x = 12
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3 years ago

A mother has two children whose ages differ by 5 years. The sum of the squares of their ages is 97. The square of the mother's

svetoff [14.1K]

Answer:

41 years old.

Step-by-step explanation:

Let x represent age of younger child.

We have been given that a mother has two children whose ages differ by 5 years. So the age of older child would be $x+5$ .

The sum of the squares of their ages is 97. We can represent this information in an equation as:

$x^2+(x+5)^2=97$

Let us solve for x.

$x^2+x^2+10x+25=97$

$2x^2+10x+25-97=0$

$2x^2+10x-72=0$

Divide both sides by 2:

$x^2+5x-36=0$

$x^2+9x-4x-36=0$

$x(x+9)-4(x+9)=0$

$(x+9)(x-4)=0$

$(x+9)=0 ; (x-4)=0$

$x=-9 ; x=4$

Since age cannot be negative, therefore, age of younger child is 4 years.

Age of older child would be $x+5\Rightarrow4+5=9$

Therefore, the age of older child would be 9 years.

We have been given that the square of the mother's age can be found by writing the squares of the children's ages one after the other as a four-digit number.

Square of 4: $4^2=16$