Find the bases for Col A and Nul A, and then state the dimension of these subspaces for the matrix A and an echelon form of A b
elow.
A= 1 3 8 2 7 1 3 8 2 7
2 7 20 6 20 --- 0 1 4 2 6
-3 -12 -36 -7 -19 0 0 0 1 4
3 13 40 9 25 0 0 0 0 0
Start 4 By 5 Table 1st Row 1st Column 1 2nd Column 3 3rd Column 8 4st Column 2 5st Column 7 2nd Row 1st Column 2 2nd Column 7 3rd Column 20 4st Column 6 5st Column 20 3rd Row 1st Column negative 3 2nd Column negative 12 3rd Column negative 36 4st Column negative 7 5st Column negative 19 4st Row 1st Column 3 2nd Column 13 3rd Column 40 4st Column 9 5st Column 25 EndTable
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Start 4 By 5 Table 1st Row 1st Column 1 2nd Column 3 3rd Column 8 4st Column 2 5st Column 7 2nd Row 1st Column 0 2nd Column 1 3rd Column 4 4st Column 2 5st Column 6 3rd Row 1st Column 0 2nd Column 0 3rd Column 0 4st Column 1 5st Column 4 4st Row 1st Column 0 2nd Column 0 3rd Column 0 4st Column 0 5st Column 0 EndTable
A basis for Col A is given by
StartSet nothing EndSet
(Use a comma to separate vectors as needed.)
The dimension of Col A is
3.
A basis for Nul A is given by
StartSet nothing EndSet
(Use a comma to separate vectors as needed.)
The dimension of Nul A .
1 answer:
Answer:
skip counting by 0
Step-by-step explanation:
skipcount by 0 to get to 100 for the third column.
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Option B
Because you would not make as much money
Solve for n by simplifying both sides of the equation, then isolating the variables.
n=54
Hope I helped
Answer: x>=200
Step-by-step explanation:
The answer is
M=1
Your welcome:)
Answer: C
<u>Step-by-step explanation:</u>
Varies inversely means xy = k
A. 1(-3) = -3
2(-9) = -18
-3 ≠ -18
B. 1(-6) = -6
2(-12) = -24
-6 ≠ -24
C. 1(6) = 6
2(3) = 6
3(2) = 6
6 = 6 = 6 This works!
D. 1(-3) = -3
2(2) = 4
-3 ≠ 4
The only table that has the same k-value is option C.