Answer:
1
Step-by-step explanation:
<h2>Given, y = b m x m</h2><h2>y' = -b m x (m+1)</h2><h2>At any point (x1,y1)</h2><h2 /><h2>Equation of tangent is given by </h2><h2>y - y1 </h2><h2>------- = -b m x1 -(m+1)</h2><h2>x - x1</h2><h2>Y intercept = - m</h2><h2>X intercept = (m-1) × 1</h2><h2> m </h2><h2>Area bounced = 1 (m - 1)×1</h2><h2> ---- ---------------------- x m</h2><h2> 2 m</h2><h2>For area to be constant, m = 1</h2>
Pi*radius squared= area of a circle
3.14*2^2=12.56yd^2
pi*diameter=circumference
3.14*4=12.56yd
area of surface around the cylinder=circumference*height
12.56*6=75.36yd^2
area of surface around the cylinder+ (area of circle*2)= surface area
75.36+(12.56*2)=100.48
the answer should by 100.48 yards squared
hope this helps
The nth equation is 3780 - 39n
Answer:
1.62 seconds
Step-by-step explanation:
h = -16t² + 24t + 16.4
The initial height is 16.4 feet. The snowboarder lands 3.2 feet below this, or at a height of 13.2 feet.
13.2 = -16t² + 24t + 16.4
16t² − 24t − 3.2 = 0
Solve with quadratic formula:
t = [ -(-24) ± √((-24)² − 4(16)(-3.2)) ] / 2(16)
t = [ 24 ± √(576 + 204.8) ] / 32
t = 1.62
The snowboarder is in the air for 1.62 seconds.
