Answer:
64√2 or 64 StartRoot 2 EndRoot
Step-by-step explanation:
A 45-45-90 traingle is a special traingle. Let's say one of the leg of the triangle is x. The other one is also x because of the isosocles triangle theorem. Therefore, using the pytagorean theorem, you find that x^2+x^2=c^2. 2(x)^2=c^2. You then square root both sides and get c= x√2.
Therefore, the two legs are x and the hypotenuse is x√2. x√2=128 because the question says that the hypotenuse is 128. Solve for x by dividing both sides by √2. X=128/√2. You rationalize it by multiplying the numberator and denominator of the fraction by √2. √2*√2= 2.
X=(128√2)/2= 64√2 cm.
Since X is the leg, the answer would be 64√2
Answer:
About $4425.69
Step-by-step explanation:
Input the values into the equation to get: $4253(1+0.01)^4=
$4425.69(when rounding to the nearest cent)
Scientific notation
Explanation:
…
Answer: x = 12
midsegment is 16 units long
bottom side is 32 units long
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Work Shown:
The midsegment 2x-8 is parallel to the bottom side 2x+8
The bottom side is twice as long compared to the midsegment (since the midsegment is half the length of the bottom side).
We can say
bottom side = 2*(midsegment)
2x+8 = 2*(2x-8)
2x+8 = 4x-16
2x-4x = -16-8
-2x = -24
x = -24/(-2)
x = 12
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Extra info:
Now that we know x, we can find the length of those segments
midsegment = 2x-8 = 2*12-8 = 24-8 = 16
bottom side = 2x+8 = 2*12+8 = 24+8 = 32
Note the bottom side (32) is exactly twice as long compared to the midsegment (16). This confirms we have the correct x value.
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