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chubhunter [2.5K]
2 years ago
5

8x + 4y = 16 7y = 15 - x

Mathematics
1 answer:
Cloud [144]2 years ago
3 0

Answer:

The answer is x=1 and y=2 hope it helps

Step-by-step explanation:

 

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How do you solve 3^(4x) = 3^(5-x)?
trasher [3.6K]
3^(4x) = 3^(5 - x)
4x = 5 - x
4x + x = 5
5x = 5
x = 5/5 = 1
x = 1
3 0
3 years ago
Thanks, & yes how did you get that
soldier1979 [14.2K]
Hello <span>Vmcdowell43

The word Thanks is a shorter way of saying Thank you. Many people use it because it is easier.

The word yes is a simple way to agree with something.

Hope that helps!
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6 0
3 years ago
A circle has a radius of 7.5 centimeters and a central angle AOB that measures 90 degrees. What is the length of the intercepted
Julli [10]
Since there are 360^{\circ} in a circle, and central \angle AOB = 90^{\circ}, you can see that the part "sliced out" by the central angle is \frac{90^{\circ}}{360^{\circ}} = \frac{1}{4} of the whole circle.

This means that the length of the intercepted arc \stackrel{\frown}{AB} is \frac{1}{4} of the circumference of the circle. So,

\stackrel{\frown}{AB} = \frac{1}{4}(2 \pi r) = \frac{1}{4}(2 \pi (7.5 cm)) = \bf \frac{15 \pi}{4} cm



6 0
3 years ago
Twice the difference between a number and 4 is twenty. Find the number.
kogti [31]

Answer:

D 14

Step-by-step explanation:

Let x be the number

2(x-4) = 20

Divide each side by 2

2/2(x-4) = 20/2

x-4 = 10

Add 4 to each side

x-4+4 = 10+4

x = 14

7 0
3 years ago
Read 2 more answers
Calculate the average travel time for each distance, and then use the results to calculate. A 6-column table with 3 rows in the
BigorU [14]

The average travel time is simply the mean travel time between the given points

  • The average time that it takes for the car to travel the first 0.25m is 2.23s.
  • The average time to travel just between 0.25m and 0.50m is 0.9s.
  • Given the time taken to travel the second 0.25 m section, the velocity would be 0.28m/s.

<u>(a) The average time to travel the first 0.25m</u>

The time travel in the first 0.25m are: 2.24s, 2.21s and 2.23s.

So, the average time to travel is:

Time = \frac{2.24s + 2.21s + 2.23s}{3}

Time = \frac{6.68s}{3}

Time = 2.23s

<u>(b) The average time to travel just between 0.25m and 0.50m</u>

The time travel in the 0.50m are: 3.16s, 3.08s and 3.15s.

So, the average time to travel this distance is:

Time = \frac{3.16s + 3.08s + 3.15s}{3}

Time = \frac{9.39s}{3}

Time = 3.13s

The average time to travel between both distance is the difference between the average time of each distance.

So, we have:

Average = 3.13s - 2.23s

Average = 0.9s

<u>(c) The velocity in the second 0.25m section</u>

The distance and time are:

Distance = 0.25m

Time = 0.9s

So, the velocity is:

Velocity = \frac{Distance}{Time}

This gives

Velocity = \frac{0.25m}{0.9s}

Velocity = 0.28m/s

Read more about distance, velocity and time at:

brainly.com/question/4931057

6 0
3 years ago
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