Answer:
See below.
Step-by-step explanation:
Party A
y = x^2 + 1
For each value of x in the table, substitute x in the equation with that value and evaluate y.
x = -2: y = (-2)^2 + 1 = 4 + 1 = 5
x = -1: y = (-1)^2 + 1 = 1 + 1 = 2
Do the same for x = 0, x = 1, x = 2
x y
-2 5
-1 2
0 1
1 2
2 5
Part B
Look at points (-2, 5) and (-1, 2). The change in x from (-2, 5) to (-1, 2) is 1. The change in y is -3.
Now let's look at two other points which have a change in x of 1. Look at points (0, 1) and (1, 2). The change in x from (0, 1) to (1, 2) is 1. The change in y is 1.
You can see that for the first two points, a change of 1 in x produces a change of -3 in y, but for the second two points, the same change of 1 in x produce a change of 1 in y. Since the same change of x does not always produce the same change in y, the function is nonlinear.
Answer: A
5 liters (L) of 30% bleach solution contains 0.3×(5 L) = 1.5 L of bleach.
3 L of 50% bleach contains 0.5×(3 L) = 1.5 L of bleach, too.
Combined, you would have 8 L of solution containing 1.5 L + 1.5 L = 3 L of bleach, so the concentration of bleach is
(3 L) / (8 L) = 0.375 = 37.5%
There are a couple ways to do this, but basically you need to convert the units.
<span>7 yards x 3 ft/yard = 21 feet </span>
<span>4 yards x 3 ft/yard = 12 feet </span>
<span>So the area (in sq. ft) will be: </span>
<span>21 x 12 </span>
<span>= 252 sq. ft. </span>
<span>Alternatively, you can figure the area in square *yards* and then multiply by 9 sq. ft per sq. yard. </span>
<span>7 yards x 4 yards x 9 sq. ft/sq. yard </span>
<span>= 252 sq. ft.
hope this helps :)</span>
Horizontal distance = 48'
difference in elevation = 18"-6" = 12" = 1'
Slope of the sewer line = rise/run = 1/48 = 0.0208 = 2.08%
First you have to find the slope with the equation y2 - y1 / x2 - x1 , then once you have found the slope (slope = -2) you simply plug it into the point slope formula. y-0 = -2(x-5) solving it algebraically you should arrive at Y=-2x+10. (the 5 and 0 were plugged in are two of the X and Y points of the line which is why we plugged them into the X and Y values of the equation)
