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Alexxandr [17]
3 years ago
7

An older person is 7 years older than five times the age of a younger person. The sum of their ages is 37. Find their ages.

Mathematics
1 answer:
OLga [1]3 years ago
6 0

Answer:

older person: 32 yrs younger person: 5 yrs

Step-by-step explanation:

older person age: o

younger person age: y

o=5y+7

o+y=37

Solve with substitution:

5y+7+y=37

6y+7=37

6y=30

y=5

Plug back in:

o+5=37

o=32

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BabaBlast [244]

Answer:

156

Step-by-step explanation:

It the whole line’s angle measure would be 180 degrees. If you subtract 24 from 180 You get 156.

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Answer:

216mx meters

Step-by-step explanation:

m is in minutes so convert it in hours = 60m hrs

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6 0
3 years ago
Determine if (-2,6) and (4,12) are solutions to the system of equations:
kykrilka [37]

Answer:

Both (-2,6) and (4,12) are solutions to the system.

Step-by-step explanation:

In order to determine whether the two given points represent solutions to our system of equations, we must "plug" thos points into both equations and check that the equality remains valid.

Step 1: Plug (-2,6) into y=x+8

(6) = (-2)+8 = 6

The solution verifies the equation.

Step 2: Plug (-2,6) into 2y=x^2 + 8

2(6) = (-2)^2+8=4+8=12

The solution verifies both equations. Therefore, (-2,6) is a solution to this system.

Now we must check if the second point is also valid.

Step 3: Plug (4,12) into y=x+8

(12) = (4)+8 = 12

Step 4: Plug (4,12) into 2y=x^2 + 8

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3 0
3 years ago
Need an answer as soon as possible.
Elza [17]
Part A

Answer: The common ratio is -2

-----------------------------------

Explanation: 

To get the common ratio r, we divide any term by the previous one

One example:
r = common ratio
r = (second term)/(first term)
r = (-2)/(1)
r = -2

Another example:
r = common ratio
r = (third term)/(second term)
r = (4)/(-2)
r = -2
and we get the same common ratio every time

Side Note: each term is multiplied by -2 to get the next term

============================================================
Part B

Answer:
The rule for the sequence is 
a(n) = (-2)^(n-1)
where n starts at n = 1

-----------------------------------

Explanation:

Recall that any geometric sequence has the nth term
a(n) = a*(r)^(n-1)
where the 'a' on the right side is the first term and r is the common ratio

The first term given to use is a = 1 and the common ratio found in part A above was r = -2
So,
a(n) = a*(r)^(n-1)
a(n) = 1*(-2)^(n-1)
a(n) = (-2)^(n-1)

============================================================
Part C

Answer: The next three terms are 16, -32, 64

-----------------------------------

Explanation:

We can simply multiply each previous term by -2 to get the next term. Do this three times to generate the next three terms

-8*(-2) = 16
16*(-2) = -32
-32*(-2) = 64

showing that the next three terms are 16, -32, and 64

An alternative is to use the formula found in part B

Plug in n = 5 to find the fifth term
a(n) = (-2)^(n-1)
a(5) = (-2)^(5-1)
a(5) = (-2)^(4)
a(5) = 16 .... which matches with what we got earlier

Then plug in n = 6
a(n) = (-2)^(n-1)
a(6) = (-2)^(6-1)
a(6) = (-2)^(5)
a(6) = -32 .... which matches with what we got earlier

Then plug in n = 7
a(n) = (-2)^(n-1)
a(7) = (-2)^(7-1)
a(7) = (-2)^(6)
a(7) = 64 .... which matches with what we got earlier

while the second method takes a bit more work, its handy for when you want to find terms beyond the given sequence (eg: the 28th term)
6 0
4 years ago
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