It would be called an ecological model.
Answer:
Step-by-step explanation:
The mean SAT score is
, we are going to call it \mu since it's the "true" mean
The standard deviation (we are going to call it
) is

Next they draw a random sample of n=70 students, and they got a mean score (denoted by
) of 
The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.
- So the Null Hypothesis 
- The alternative would be then the opposite 
The test statistic for this type of test takes the form

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.
With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>
Answer:
Correct rate of change is -5; correct initial value is 3.
Step-by-step explanation:
The rate of change is the coefficient of the x term, which here is -5. So Bryan has the rate of change wrong.
The initial value of the function is found by letting x = 0. Here, we get
y = -5(0) + 3, or y = b = 3. The initial value is 3, not -5.
Answer:
The simplified form of -6.3x+14 and 1.5x-6 is -4.8x+8
Step-by-step explanation:
We have to simplify the following
-6.3x+14 and 1.5x-6
it can be written as:
=(-6.3x+14) + (1.5x-6)
Adding the like terms
=(-6.3x+1.5x)+(14-6)
= (-4.8x)+(8)
= -4.8x+8
So, the simplified form of -6.3x+14 and 1.5x-6 is -4.8x+8
If ya distribute it it comes together as 24 + 8x soo i hope this helped