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mixer [17]
2 years ago
8

Income tax returns show that the mean income of self-employed persons in a particular year was £15,000, with a standard deviatio

n of £975. A random sample of 169 returns from people in the clothing industry gave a mean income of £14,500. Did this indicate that income from self-employment in the clothing industry was significantly different?
Mathematics
1 answer:
DochEvi [55]2 years ago
6 0

Answer:

Yes, There is significant difference.

Step-by-step explanation:

Null Hypothesis , H0 : Mean income = 15000

Alternate Hypothesis , H1 : Mean income  ≠  15000

t = (x - u) / ( s / √n)

x = sample mean = 14500 here, u = population mean = 15000 here ,             s = standard deviation =  975 here  , n = sample size

t = (14500 - 15000) / (975 / √169)

-500 / 75 = - 6.66

As  calculated t value in absolute terms is > 1.96 , ie tabulated value at 95% significance level (two sided). So we reject the null hypothesis in favor of alternate hypothesis. Hence, we state that 'Mean Income ≠  15000'

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Answer:

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3 years ago
Read 2 more answers
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alisha [4.7K]

The equation that represents the relationship between the number of liters, x, and the number of liquid pints, y is y = 2.11x

<h3>How to determine the equation?</h3>

The attached table of values represents the missing piece in the question.

Start by calculating the rate of change using:

m = (y2 - y1)/(x2 - x1)

This gives

m = (14.77 - 10.55)/(7- 5)

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4 0
2 years ago
Are two equilateral triangles always similar
sukhopar [10]
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3 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

This is binomial

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2 years ago
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