F(x)=x^3-7x-6 Since I don't have the graph and this is not a perfect cube, I will have to rely on Newton :P
x-(f(x)/(dy/dx))
x-(x^3-7x-6)/(3x^2-7)
(2x^3+6)/(3x^2-7), letting x1=0
0, -6/7, -.988, -.9999, -.99999999999, -1
(x^3-7x-6)/(x+1)
x^2 r -x^2-7x-6
-x r -6x-6
-6 r 0
(x+1)(x^2-x-6)=0
(x+1)(x-3)(x+2)=0
x= -2, -1, 3
Answer: A. f(n) = 4 ∙ 2n-1
Step-by-step explanation:
because the 1st term is 4 according to your image, and then you will have to multiply that by its common difference and using your table, to get from 4 to 8 then 8 to 16 you would multiply by 2, and you would finally multiply that by n or known as the number of terms and 1 making the equation. f(n) = 4 ∙ 2n-1 I hope this is very helpful for everyone.
Answer:
y = 3x -2
Step-by-step explanation:
If the line is parallel, that means it has the same slope. The given equation had a slope of 3, so the new line must also have a slope of 3.
You can plug the given coordinates into the slope-intercept form with a slope of 3 to find your answer.
y = m*x + b
7 = 3*3 + b
7 = 9 + b
-2 = b
y = 3x -2
I Hope This Helps :D
