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zaharov [31]
3 years ago
11

The picture up above

Mathematics
1 answer:
damaskus [11]3 years ago
6 0

Answer:

its being reflected over the y-axis

Step-by-step explanation:

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Identify a temperature colder than -7.2 F. Write an inequality that relates the temperatures. Describe their positions on a hori
Angelina_Jolie [31]
One temperature colder that -7.2 F would be -9 F.

-9 < -7.2


The -9 would be 1.8 units to the left of -7.2  on  the number line.
4 0
3 years ago
2, 3, 5, 9, 17...
BARSIC [14]

Answer:

Step-by-step explanation:

i'm sure the answer is C

8 0
3 years ago
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Write four different expressions for the perimeter of a pentagon whose sides are all s-2 units long
igor_vitrenko [27]

Answer:  The answers are given below.

 

Step-by-step explanation:  Given that all the sides of a pentagon are (s-2) units long. This clearly tells us that the pentagon is a regular one with each side equal to (s-2) units.

We are to write the perimeter of the pentagon in four different expressions.

Let 'P' represents the perimeter of the pentagon.

Since it is a regular pentagon, we can write the perimeter in following four expressions.

P = (s-2) + (s-2) + (s-2) + (s-2) + (s-2),

  = 5 × (s-2),

  = 5s - 10,

  = 5s - 5×2.

Thus, these are the four expressions for the perimeter of the pentagon.

   


6 0
3 years ago
Show how to solve this
alekssr [168]

Answer:

86093440 /129140163

Step-by-step explanation:

Explanation in the Images. I can clarify further if needed.

6 0
3 years ago
insurance company checks police records on 559 accidents selected at random and notes that teenagers were at the wheel in 91 of
ss7ja [257]

Answer: (13.22\%,\ 19.34\%)

Step-by-step explanation:

Given : Sample space : n= 559

Sample proportion : \hat{p}=\dfrac{91}{559}=0.162790697674\approx0.1628

=16.28\%

Significance level : \alpha= 1-0.95=0.05

Critical value : z_{\alpha/2}=1.96

Confidence level for population proportion:-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.1628\pm (1.96)\sqrt{\dfrac{0.1628(1-0.1628)}{559}}\\\\=0.1628\pm0.030604971367\\\\\approx 0.1628\pm0.0306=(0.1322,\ 0.1934)=(13.22\%,\ 19.34\%)

Hence, 95% confidence interval for the percentage of all auto accidents that involve teenage drivers.= (13.22\%,\ 19.34\%)

7 0
4 years ago
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