We may have this planned like this:
two years is 8 quarters
<span>Assuming simple interest, </span>
You will use the formula
<span>A = P(1+rt) </span>
<span>= 400(1+8*.03) </span>
<span>= 496
</span>I think this is the answer:) Hope it helps a lot
Answer:
B
Step-by-step explanation:
That's the biggest number
Answer:
<h2>VX = 26</h2>
Step-by-step explanation:
If W is the midpoint of VX then VW = WX. Therefore we have the equation:
2x + 5 = 4x - 3 <em>subtract 5 from both sides</em>
2x = 4x - 8 <em>subtract 4x from both sides</em>
-2x = -8 <em>divide both sides by (-2)</em>
x = 4
VX = VW + WX
VX = 2x + 5 + 4x - 3 = (2x + 4x) + (5 - 3) = 6x + 2
Put the value of x = 4 to 6x + 2:
VX = 6(4) + 2 = 24 + 2 = 26
Let x =lenght, y = width, and z =height
<span>The volume of the box is equal to V = xyz </span>
<span>Subject to the surface area </span>
<span>S = 2xy + 2xz + 2yz = 64 </span>
<span>= 2(xy + xz + yz) </span>
<span>= 2[xy + x(64/xy) + y(64/xy)] </span>
<span>S(x,y)= 2(xy + 64/y + 64/x) </span>
<span>Then </span>
<span>Mx(x, y) = y = 64/x^2 </span>
<span>My(x, y) = x = 64/y^2 </span>
<span>y^2 = 64/x </span>
<span>(64/x^2)^2 = 64 </span>
<span>4096/x^4 = 64/x </span>
<span>x^3 = 4096/64 </span>
<span>x^3 = 64 </span>
<span>x = 4 </span>
<span>y = 64/x^2 </span>
<span>y = 4 </span>
<span>z= 64/yx </span>
<span>z= 64/16 </span>
<span>z = 4 </span>
<span>Therefor the dimensions are cube 4.</span>
