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Orlov [11]
3 years ago
12

What is the real answer to that

Mathematics
1 answer:
mash [69]3 years ago
4 0

Answer:

Picture?? lol

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A hospital uses cobalt-60 in its radiotherapy treatments for cancer patients. Cobalt-60 has a half-life of 7
NeTakaya

Answer:

We have 197 g of Co-60 after 18 months.

Step-by-step explanation:

We can use the decay equation.

M_{f}=M_{i}e^{-\lambda t}

Where:

  • M(f) and M(i) are the final and initial mass respectively
  • λ is the decay constant (ln(2)/t(1/2))
  • t(1/2) is the half-life of Co
  • t is the time at the final amount of m

M_{f}=228e^{-\frac{ln(2)}{7} 1.5}    

M_{f}=197\: g    

<u>Therefore, we have 197 g of Co-60 after 18 months.</u>

I hope it helps you!

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3 years ago
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The answer to you is:

True

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