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3 years ago

11

Ackrabbits are capable of reaching speeds up to 40 miles per hour. How fast is this in feet per second? (Round to the nearest wh

ole number.)
5,280 feet = 1 mile

27 feet per second
59 feet per second
132 feet per second
288 feet per second

1 answer:

Tema [17]3 years ago

6 0

The answer is 58.67 ft per second

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The function f(x) = x2 is translated 7 units to the left and 3 units down to form the function g(x). Which represents g(x)?

nignag [31]

Answer:

B. g(x)=(x+7)^2-3

Step-by-step explanation:

Vertex form is F(x)= a(x-h)^2+k

a is the reflection

h and k are the vertex (x,y) = (h,k)

in this case there is no shrink or stretch (a)

if it is translating left or right it is "h". In this case it is translated left so its -7. However if you look at vertex form it is "x-h" so -7-7= +7

If it translating up or down it is "K". In this case it is translated down so its -3.

If it was translated up or right then its positive. If it was translated down or left its negative.

After you figure out what h and k are then you just plug it in. h=-7, k=-3

so the answer in vertex form is, g(x)=(x+7)^2-3

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2 years ago

Yx*2; use x=7,And y=2

Lyrx [107]

Answer:

28

Step-by-step explanation:

First you plug in your x, and y to get (2)(7)*2

Then you just have to times them all together and you get 2*7=14 then 14*2=28

6 0

3 years ago

A 99% confidence interval for the mean μ of a population is computed from a random sample and found to be 6 ± 3. We may conclude

valentina_108 [34]

Answer:

A. there is a 99% probability that μ is between 3 and 9.

Step-by-step explanation:

From a random sample, we build a confidence interval, with a confidence level of x%.

The interpretation is that we are x% sure that the interval contains the true mean of the population.

In this problem:

99% confidence interval.

6 ± 3.

So between 6-3 = 3 and 6 + 3 = 9.

So we are 99% sure that the true population mean is between 3 and 9.

So the correct answer is:

A. there is a 99% probability that μ is between 3 and 9.

4 0

3 years ago

Read 2 more answers

Help me please. I am having troubles with my math homework.

jeyben [28]

Answer: (3) f(8) = g(8)

<u>Step-by-step explanation:</u>

Let's compare the values of f(x) and g(x) when x = 0, 2, 8, and 4

<u> f(x) </u> <u> g(x) </u> <u>Comparison</u>

f(x) = 2x - 3 $g(x)=\dfrac{3}{2}x+1$

f(0) = 2(0) - 3 $g(0)=\dfrac{3}{2}(0)+1$

= -3 = 1 f(0) < g(0)

f(2) = 2(2) - 3 $g(2)=\dfrac{3}{2}(2)+1$

= 1 = 4 f(2) < g(2)

f(8) = 2(8) - 3 $g(8)=\dfrac{3}{2}(8)+1$

= 13 = 13 f(8) = g(8)

f(4) = 2(4) - 3 $g(4)=\dfrac{3}{2}(4)+1$

= 5 = 7 f(4) < g(4)

The only statement provided that is true is f(8) = g(8)

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3 years ago

A shipment of 11 printers contains 2 that are defective. Find the probability that a sample of size 2, drawn from the 11, will

svet-max [94.6K]

The required probability is $\frac{36}{55}$

<u>Solution:</u>

Given, a shipment of 11 printers contains 2 that are defective.

We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.

Now, we know that, $\text { probability }=\frac{\text { favourable outcomes }}{\text { total outcomes }}$

Probability for first draw to be non-defective $=\frac{11-2}{11}=\frac{9}{11}$

(total printers = 11; total defective printers = 2)

Probability for second draw to be non defective $=\frac{10-2}{10}=\frac{8}{10}=\frac{4}{5}$

(printers after first slot = 10; total defective printers = 2)

Then, total probability $=\frac{9}{11} \times \frac{4}{5}=\frac{36}{55}$

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3 years ago