Answer:
|x|=6 we have x1=-6 x2=6
|x|=3.2 we have x1=-3.2 x2=3.2
|x|=0 x=0
No, 2 of the 5x7 would actually take up. 10x14
Answer:
no solution
Step-by-step explanation:
both sides = -2 when we substitute n for 2 so
therefore it doesn’t have solution or doesn’t satisfy the inequality
Cuz n should be > not equal
Answer:
the vertex is at (2, 8) and the axis of symmetry is x = 2
Step-by-step explanation:
In h(x)=−2x2+8x please use the symbol " ^ " to indicate exponentiation:
h(x)=−2x^2+8x
This is a quadratic equation with coefficients a = -2, b = 8 and c = 0.
The axis of symmetry equation is x = -b/ (2a).
-8
Here, with a = -2 and b = 8, the axis of symmetry is x = --------- = 2
2(-2)
To find the y-coordinate of the vertex, substitute 2 for x in h(x)=−2x^2+8x, obtaining
h(2) = -2(2)^2 + 8(2) = -2(4) + 16 = 8
In summary, the vertex is at (2, 8) and the axis of symmetry is x = 2.
Solution
Here the first term = -2
5th term = -1/8
Now we have to find the common ratio (r)
Fifth term A5 = -1/8
-1/8 =
Here 
Plug in
in the fifth term and find the value of r.
-1/8 = -2


Taking 4th root, we get
r = 
Now let's find the second term.
first term *r = -2 *1/2 = -1
2nd term = -1
3rd term = second term * 1/2 = -1 * 1/2 = -1/2
4th term = 3rd term *r = -1/2 *1/2 = -1/4
Thank you :)