Answer:
Option A
Step-by-step explanation:
Given:
Center of circle = (h,k)= (3,8)
Radius = r = 5
The standard form of equation of circle with center and radius is:

Therefore, the general form of the equation of circle given is:

Hence, option A is correct ..
Sin (A + B) = sin A cos B + cos A Sin B
<span>Cos (A - B) = cos A cos B + sin A sin B </span>
<span>=> (SinACosB+ CosASinB) (CosACosB +SinASinB) </span>
<span>=>SinACosACos^2B+Sin^2ACosBSinB+Cos^2A... </span>
<span>=>SinACosA(Cos^2B+Sin^2B) +SinBCosB(Sin^2A+Cos^2A) </span>
<span>we know that Sin^2+Cos^2=1 </span>
<span>=>SinACosA(1)+SinBCosB(1) </span>
<span>=SinACosA+SinBCosB </span>
<span>Proved
</span>
On a coordinate plane it is negetive 5
Answer:
-135
Step-by-step explanation:
-5(9 - 6k)
Let k = -3
-5 ( 9 - 6*-3)
-5 ( 9 + 18)
-5 ( 27)