This is a great question, but it's also a very broad one. Please find and post one or two actual rational expressions, so we can get started on specifics of how to find vertical and horiz. asymptotes.
In the case of vert. asy.: Set the denom. = to 0 and solve for x. Any real x values that result indicate the location(s) of vertical asymptotes.
Answer:
x^2+2x+5
Step-by-step explanation:
Can't really explain on a computer, but if you want to know how to do it look at www.emathhelp.net
3! possible ways for appetizers
5! possible ways for soups
10! entrees for lunch special
Therefore,
3! 5! 10! ways of ordering the lunch special menu.
Hope I helped :)
Total surface area of the cylinder= 2*area of base+lateral area=
=2*1962.5 + <span>194.2 = 4119.2 cm²
1m=100 cm
1m² = (100 cm)²
1m²=10000cm²
</span>4119.2 cm² *(1m²/10000 cm²)= 0.41192 m²
Answer:
This is an isosoles triangle because it has two congruent sides, and two congruent angles. Brainliest pls :)
