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djyliett [7]
3 years ago
11

How to convert from rectangular to polar coordinates pre calc?

Mathematics
1 answer:
Verizon [17]3 years ago
6 0
<span>Given the polar coordinate (r,θ), write. x=rcos θ and. y=rsin θ.Evaluate cos θ and. sin θ.Multiply cos θ by. r. to find the x-coordinate of the rectangular form.<span>Multiply sin θ by. r. to find the y-coordinate of the rectangular form.</span></span>
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Pls help 25 points and brainliest.
puteri [66]

This is an equation that calculates potential energy and converts the value into its commercial unit.

<u>Step-by-step explanation:</u>

Step 1:

Given equation is 2 kg × 9.81 m/s² × 40 m. From the units, find the corresponding measurements. kg is the unit of mass (m), 9.81 m/s² is the acceleration due to gravity (g) and m is the unit of length or height (h).

This shows that this equation is to find potential energy. It is then converted into the commercial unit of energy (Joules).

⇒ Potential Energy = mgh = 2 kg × 9.81 m/s² × 40 m

                                            = 784.8 kg m²/s²

                                            = 784.8 N-m (Since unit of force, 1 N=kg m/s²)

                                            = 784.8 J (1 Newton-m = 1 Joule)

     

3 0
3 years ago
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Write area or perimeter for each situation. Carpeting a floor
Fynjy0 [20]
Hello!

Your answer is area because area refers to a region, while perimeter only refers to the surrounding boundary of a figure. If you're going to carpet a floor, you will want to cover the entire area of the floor.
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3 years ago
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Which situation is represented by the equation x+10=26?
zhuklara [117]

Answer:

16

Step-by-step explanation:

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I NEED HELP!! please show all work
PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

4^{5x} = 3^{x-2}

\implies \log 4^{5x} = \log 3^{x-2}

Drop the exponents:

\implies 5x \log 4 = (x-2) \log 3

Expand the right side:

\implies 5x \log 4 = x \log 3 - 2 \log 3

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

\implies 5x \log 4 - x \log 3 = - 2 \log 3

\implies x (5 \log 4 - \log 3) = - 2 \log 3

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}

You can stop there, or continue simplifying the solution by using properties of logarithms:

\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }

\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }

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You can condense the solution further using the change-of-base identity,

\implies \boxed{x = -\log_{\frac{1024}3}9}

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2 years ago
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