Answer:
13/17
Step-by-step explanation:
Answer:
can yhu see the answer i put?
Step-by-step explanation:
Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval:
(-15,-10).
<h3>What is the slope of the tangent line to a function f(x) at point x = x0?</h3>
It is given by the derivative at x = x0, that is:
.
In this problem, the function is:
![f(x) = 0.2x^2 + 5x - 12](https://tex.z-dn.net/?f=f%28x%29%20%3D%200.2x%5E2%20%2B%205x%20-%2012)
Hence the derivative is:
![f^{\prime}(x) = 0.4x + 5](https://tex.z-dn.net/?f=f%5E%7B%5Cprime%7D%28x%29%20%3D%200.4x%20%2B%205)
For a slope of -1, we have that:
0.4x + 5 = -1
0.4x = -6
x = -15.
For a slope of 1, we have that:
0.4x + 5 = 1.
0.4x = -4
x = -10
Hence the interval is:
(-15,-10).
More can be learned about derivatives and tangent lines at brainly.com/question/8174665
#SPJ1
Answer:
1/9 x 1/9 just do it across... 1/81
Step-by-step explanation: