Write the quadratic equation in general form and then choose the value of "b."

2 answers:

4 0

First of all to transfer (2x - 1)(x + 6) = 0 into a form where we can plug it into the quadratic formula we need to use the FOIL method.

(2x - 1)(x + 6) = 0
 becomes
2x*x+2x*6+-1*x+-1*6
which simplifies to
2x^2 + 12x - x - 6
and then we add like terms to get
2x^2 + 11x - 6

now that it is in the correct form we can identify "a" "b" and "c" by following this form
ax^2 + bx + c
looking back at the equation we got earlier
2x^2 + 11x - 6

a=2,b=11,and c=-6

Korvikt [17]3 years ago

3 0

Answer:

The answer is b=11

Step-by-step explanation:

You are welcome.

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Let f(x) = tan(x) - 2/x. Let g(x) = x^2 + 8. What is f(x)*g(y)?

Tema [17]

Answer:

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

Step-by-step explanation:

We are given that

$f(x)=tan(x)-\frac{2}{x}$

$g(x)=x^2+8$

We have to find $f(x)\times g(y)$

To find the value of $f(x)\times g(y)$ we will multiply f(x) by g(y)

$g(y)=y^2+8$

Now,

$f(x)\times g(y)=(tanx-\frac{2}{x})(y^2+8)$

$f(x)\times g(y)=tan(x)(y^2+8)-\frac{2}{x}(y^2+8)$

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

Hence,

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

5 0

2 years ago

Square root of 192 simplified

Sonja [21]

You must factoring the number 192, you will get 192=2^6*3, so you have square root(2^6*3)=2^(6/2)*root(3) applying enhancing property.
Solve the exponent and you get =2^3*root(3)= 8*root(3)

8 0

3 years ago

Can someone help me with this one

bonufazy [111]

Answer:

$x(2x+1)(x-2)$