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mixer [17]
3 years ago
6

Write the quadratic equation in general form and then choose the value of "b."

Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
4 0
First of all to transfer <span>(2x - 1)(x + 6) = 0 into a form where we can plug it into the quadratic formula we need to use the FOIL method.

</span><span>(2x - 1)(x + 6) = 0
</span> becomes
2x*x+2x*6+-1*x+-1*6
which simplifies to
2x^2 + 12x - x - 6
and then we add like terms to get
2x^2 + 11x - <span>6
</span>
now that it is in the correct form we can identify "a" "b" and "c" by following this form
ax^2 + bx + c
looking back at the equation we got earlier
2x^2 + 11x - <span>6</span>

a=2,b=11,and c=-6

Korvikt [17]3 years ago
3 0

Answer:

The answer is b=11

Step-by-step explanation:

You are welcome.

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Solve P = 8/3 R + 30 for R.
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Step-by-step explanation:

subtract 30 from each side to get:

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inysia [295]
<span>1. 5564÷91
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91 rounds to 9
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2. </span><span>5391÷25
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25 is 1/4 of 100.
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3 years ago
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• y = -6x-5

Step-by-step explanation:

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2 years ago
If an open box has a square base and a volume of 115 in.3 and is constructed from a tin sheet, find the dimensions of the box, a
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Let h = height of the box,
x = side length of the base.

Volume of the box is  V=x^{2} h = 115. 
So h = \frac{115}{ x^{2} }

Surface area of a box is S = 2(Width • Length + Length • Height + Height • Width).
So surface area of the box is
S = 2( x^{2}  + hx + hx)  \\ = 2 x^{2}  + 4hx  \\  = 2 x^{2}  + 4( \frac{115}{ x^{2} } )x
= 2 x^{2} + \frac{460}{x}
The surface are is supposed to be the minimum. So we'll need to find the first derivative of the surface area function and set it to zero.

S' = 4x- \frac{460}{ x^{2} }  = 0
4x = \frac{460}{ x^{2} }  \\  4x^{3} = 460  \\ x^{3} = 115  \\ x =  \sqrt[3]{115} = 4.86
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So the box is 4.86 in. wide and 4.87 in. high. 

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