Answer:
(1, 10)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
-5x + 6y = 55
4x + 3y = 34
<u>Step 2: Rewrite Systems</u>
4x + 3y = 34
- Multiply everything by -2: -8x - 6y = -68
<u>Step 3: Redefine Systems</u>
-5x + 6y = 55
-8x - 6y = -68
<u>Step 4: Solve for </u><em><u>x</u></em>
<em>Elimination</em>
- Combine equations: -13x = -13
- Divide -13 on both sides: x = 1
<u>Step 5: Solve for </u><em><u>y</u></em>
- Define equation: 4x + 3y = 34
- Substitute in <em>x</em>: 4(1) + 3y = 34
- Multiply: 4 + 3y = 34
- Isolate <em>y</em> term: 3y = 30
- Isolate <em>y</em>: y = 10
Answer:
-1 1/9
Step-by-step explanation:
2x + 7x = -10 (equation)
9x = -10 (combine like terms)
x = -10/9 (move the 9 over)
x = -1 1/9 (simplify)
The greatest number of people that they may invite and still stay within their budget is 130 people.
The standard form of a linear equation is given by:
y = mx + b
Where y is a dependent variable, x is an independent variable, m is the slope of the line (the rate of change), b is the y intercept (that is the initial value of y).
Let y represent the budget for x number of people.
Since the reception hall charges a $80 cleanup fee plus $34 per person, hence this can be represented by the function:
y = 34x + 80
They have budgeted $4,500 for their reception. Therefore the greatest number of people can be found from:
4500 = 34x + 80
34x = 4420
x = 130 people
Therefore the greatest number of people that they may invite and still stay within their budget is 130 people.
Find out more at: brainly.com/question/24834234
I got the answer 9.12. In the hundredths place, it would be 2.
Hope this helps! :D
