A=g
v=⌠g dt
v=gt+C, where C=v initial
v=gt+vi
h=⌠v dt
h=gt^2/2+vit+C, where C=h initial
h=gt^2/2+vit+hi
We are told that vi=42 ft/s, hi=0, and we know g≈-32 ft/s^2 so
h(t)=-16t^2+42t
The ball will hit the ground when h=0 so
-16t^2+42t=0
-2t(8t-21)=0, since t>0
8t-21=0
8t=21
t=21/8
t=2.625 sec
t≈2.6 sec (to nearest tenth of a second)
Option D:
Segment DF
Solution:
Let us first define the relationship between the side and angle in triangle.
<u>Relationship between the side and angle in triangle:</u>
- The shortest side is always opposite to the smallest interior angle.
- The largest side is always opposite to the largest interior angle.
To find the largest side in ΔDEF:
Largest angle in ΔDEF is ∠E = 73°
So, the side opposite to 73° is DF.
Therefore, Option D is the correct answer.
Hence the segment DF is the longest side in the ΔDEF.
Answer:
14
Step-by-step explanation:
subtracting by 11 gets you 14
Answer:
YZ = 8.5
Step-by-step explanation:
Since RY is an angle bisector then the ratio of the sides of the triangle are equal to the corresponding ratio of the base, that is
= 
, substitute values
= 
( cross- multiply )
7YZ = 59.5 ( divide both sides by 7 )
YZ = 8.5
Answer:
8000,I think this is right answer
