For the first digit you are choosing from 2 digits
for the second digit you are choosing from 2 digits
for the third digit you are choosing from 2 digits
2*2*2=8
111
110
011
101
000
001
100
010
However......
A number doesn't usually start with a 0 or 0s.
Therefore, if you want 3-digit numbers and not just permutations using 0 and 1, then you must eliminate
011, 000, 001, and 010
Seeing that the first digit can't be 0, you choose from 1, then 2, and then 2 digits again; 1*2*2=4 numbers
You choose which answer best suits your problem.
Answer:
x^2-7x+8=0
Step-by-step explanation:
(x+1)(x-8)=0
x^2-7x+8=0
Answer:
T´(z)=n^2s/4*i
Step-by-step explanation:
T(z)=d/dz(sin^2*z/4)
T´(z)=d/dz(sn^2zi/4)
T´(z)=d/dz(sn^2z/4*i)
T´(z)i*d/dz(sn^2z/4)
T´(z)=n^2s/4*i
Simplify
Answer:
add this and (5 × 5 × 5) × (5 × 5 × 5 × 5 × 5
Step-by-step explanation:
Answer: 9 Apples
Step-by-step explanation:
Given the following :
Total number of bags = 12
Mean of the distribution(m) = 8
Number of apples (x):
6 - - - - 7 - - - - 8 - - - - 9 - - - - 10
Frequency (f) :
1 - - - - 4 - - - - 2 - - - - 3 - - - - 1
Therefore :
Let number of apples in the 12th bag = y
Frequency of 12th bag : (12 - 11) = 1
Mean of distribution(m) :
Sum of ( f * x) / sum of f
Sum of (f * x) = (6*1)+(7*4)+(8*2)+(9*3)+(10*1)+(y*1)
Sum of (f * x) = (6+28+16+27+10+y) = 87 + y
Sum of f = 12
From :
m = Sum of ( f * x) / sum of f
8 = (87 + y) / 12
87 + y = 12 * 8
87 + y = 96
y = 96 - 87
y = 9
Number of apples in 12th bag is 9 apples
