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HACTEHA [7]
4 years ago
7

Enter an absolute-value equation whose solutions are graphed on the number line. -1 1

Mathematics
1 answer:
lora16 [44]4 years ago
5 0

can you put a picture or sum i dont understand

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Pen has 56 vegetable in his garden he has 7 times as many onions as he has cucumber how many onions dose he have
irinina [24]

he has 392 in his garden, just do 7 X 56

4 0
3 years ago
Read 2 more answers
If A = 3r^2h^2, and (rh) increases by 100%, then the new A is how many times greater than the old A? PLEASE HELP ME!!! (Specify
Maslowich

Answer: the answer is 3

Step-by-step explanation:

An increase of 100% in the value of (rh) means the value doubles. When that doubled value is squared, the new area is 4 times the old area.The question asks how many times GREATER the new A is than the old A. 4 times AS LARGE AS is a 300% INCREASE, which is 3 TIMES LARGER THAN.So the grammatically correct answer is 3 

3 0
2 years ago
If WXY is equilateral and WZY is<br> isosceles, find each missing measure.
timurjin [86]

Answer:

m∠1 = 60°

m∠2 = m∠4 = 39°

m∠3 = m∠5 = 21°

Step-by-step explanation:

ΔWXY is a equilateral angle,

Therefore, all angles of the the triangle are equal in measure.

m∠W + m∠X + m∠Y = 180°

3m∠W = 180°

m∠W = 60°

Since, ΔWZY is an isosceles triangle,

m∠3 = m∠5

m∠3 + m∠Z + m∠5 = 180°

m∠3 + 138° + m∠3 = 180°

2m∠3 = 180 - 138

m∠3 = 21°

Therefore, m∠3 = m∠5 = 21°

Since, m∠2 + m∠3 = 60°

m∠2 = 60 - 21

        = 39°

Since, m∠4 + m∠5 = 60°

m∠4 = 60 - 21

        = 39°

m∠1 = 60°

7 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Lilit [14]

Answer:  A & B are the same answer --> 96, max

<u>Step-by-step explanation:</u>

Consider m is the degree of the numerator (top) and n is the degree of the denominator (bottom). Then the horizontal asymptote (H.A.) is based on the relationship between m and n:

  • If m > n, then there is no H.A.
  • If m = n, then y = coefficient of numerator ÷ coefficient of denominator
  • If m < n, then y = 0

In the given problem, m = 1 and n = 1 so the H.A. is:

y=\dfrac{60}{0.625}\quad \rightarrow \quad y=96

This is the maximum number of moose that the forest can sustain at one time.

4 0
4 years ago
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Factor the expression x^2-100
slava [35]
This is a difference of perfect squares.
(x+10)(x-10)
7 0
4 years ago
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