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3 years ago

3(x+5)-10 = -2(x+10)

Mathematics

1 answer:

ryzh [129]3 years ago

3 0

Answer:

x=−5

Step-by-step explanation:

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6.3 covert to fractional form like a fraction and get a like and brainiest !

Lina20 [59]

Fractional form: 63/10 or 6 3/10.

8 0

3 years ago

4.) Complete the equations of the system in slope-intercept form. Use a decimal for the slope if necessary.

marissa [1.9K]

The slope is found by $y_{2} -y_{1} / x_{2} - x_{1}$
Line 1: y2 is 6, y1 is 4, x2 is 2, x1 is -2
6-4/2- -2= 2/4=1/2

Slope intercept is written as y= mx+b. m is the slope, and b is the intercept (the intercept is the value of y when x is 0). To find out the intercept, we plug in values of y, m and x
4= 1/2(-2) +b
4=-1+b
5=b
The equation for line 1 is y= 1/2x +5
Using the same formulas as above, the equation for line 2 is y= 3x+4
The solution to the system is a point where both lines would meet in the graph, or a set of x and y values that satisfies both equations.
y= 3x+4
y= 1/2x+5
3x+4 = 1/2x+5
3x= 1/2x +5 -4
3x= 1/2x +1
3x-1/2x= 1
2.5x=1
2.5x/2.5=1/2.5
x=0.4
Plug 0.4 into the slope intercept equation
y= 3(0.4) +4
y= 1.2 +4
y=5.2

y= 1/2(0.4) +5
y= 0.2 +5
y= 5.2
The solution is 0.4, 5.2

The other set of lines
Line 1: y= 3x+2
Line 2: y= -2x +7
Solution: 1,5

4 0

4 years ago

Then, the dot ran from −34 to −66. What distance did it cover? If this run took the dot 5 minutes, what was its average speed?

Maurinko [17]

Answer:

6.4

Step-by-step explanation:

since the absolute value of everything is positive, we can subtract 66-34, to learn that it covered 32 units, in means of distance, and then 32 divided by 5 is 6.4, which mean it covered an average of 6.4 units per minute

5 0

4 years ago

The floor of a canyon has an elevation of −14.5−14.5 feet. Erosion causes the elevation to change by −1.5−1.5 feet per year. How

Alona [7]

The canyon starts at an elevation of (-14.5). After each year, the elevation drops by (-1.5). The equation that could be written for this, then, would be (-14.5 - 1.5x = -31). First, we could add 14.5 to both sides of the equation to isolate the unknown. This would leave -1.5x = -16.5. Next, we can remove the negative signs so both sides of the equation are positive and easier to work with. This leaves 1.5x = 16.5. Finally, dividing both sides by 1.5 gives us "x = 11", which means that after 11 years, the canyon floor will be at -31 feet.

4 0

4 years ago

The 4th and the last terms of an A.P. are 11 and 89 respectively. If there are 30 terms in the A.P., find the A.P. and its 23rd

Natali5045456 [20]

$\underline{\underline{\large\bf{Given:-}}}$

$\red{\leadsto}\:$ $\textsf{}$ $\sf Number \: of \:terms \: in \: A.P,n = 30$

$\red{\leadsto}\:$ $\textsf{}$ $\sf Fourth \: term ,a_4 = 11$

$\red{\leadsto}\:$ $\textsf{}$ $\sf last\:term, a_{30} = 89$

$\underline{\underline{\large\bf{To Find:-}}}$

$\orange{\leadsto}\:$ $\textsf{ }$ $\sf The \: A.P.$

$\orange{\leadsto}\:$ $\textsf{ }$ $\sf 23rd\: term, a_{23}$

$\\$

$\underline{\underline{\large\bf{Solution:-}}}\\$

The nth term of A.P is determined by the formula-

$\green{ \underline { \boxed{ \sf{a_n = a+(n-1)d}}}}$

where

$\sf a = first \:term$
$\sf a_n = nth \: term$
$\sf n = number \:of \:terms$
$\sf d = common \: difference$

Since ,

$\sf a_4 = 11$

$\longrightarrow$ $\sf a+(4-1) d= 11$

$\longrightarrow$ $\sf a+3d= 11\_\_\_(1)$

$\sf a_{30}= 89$

$\longrightarrow$ $\sf a+(30-1)d=89$

$\longrightarrow$ $\sf a+29d= 89\_\_\_(2)$

Subtracting equation (1) from equation(2)

$\begin{gathered}\\\implies\quad \sf a+29d-(a+3d) = 89-11 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf a+29d-a-3d = 78 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf a-a+29d-3d = 78 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf 26d = 78 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf d = \frac{78}{26} \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf d = 3 \\\end{gathered}$

Putting the value of d in equation (1) -

$\begin{gathered}\\\implies\quad \sf a+3(3) = 11 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf a = 11-9 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf a = 2 \\\end{gathered}$

First term of A.P, a = 2

Second term of A.P., $\sf a_2= 2+(2-1)\times 3$

$\quad\quad\quad\sf =2+3$

$\quad\quad\quad\sf =5$

Third term of A.P., $\sf a_3= 2+(3-1)\times 3$

$\quad\quad\quad\sf =2+6$

$\quad\quad\quad\sf =8$

$\longrightarrow$ Thus , The A.P is 2,5,8,. . . . . .

Now,

$\begin{gathered}\\\implies\quad \sf a_n = a+(n-1)d \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf a_{23 }= 2+(23-1)\times 3 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf a_{23} = 2+22 \times 3 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf a_{23} = 2+66 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf a_{23} = 68 \\\end{gathered}$

$\longrightarrow$ Thus , 23rd term is 68.

3 0

3 years ago